// Problem: I love you
// Contest: NowCoder
// URL: https://ac.nowcoder.com/acm/contest/20960/1013
// Memory Limit: 262144 MB
// Time Limit: 2000 ms
// 2022-03-16 14:00:28
//
// Powered by CP Editor (https://cpeditor.org)
#include<bits/stdc++.h>
using namespace std;
#define rep(i,l,r) for(int i=(l);i<=(r);i++)
#define per(i,l,r) for(int i=(l);i>=(r);i--)
#define ll long long
#define mset(s,t) memset(s,t,sizeof(t))
#define mcpy(s,t) memcpy(s,t,sizeof(t))
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(),(x).end()
#define SZ(x) ((int)(x).size())
#define mp make_pair
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> Vll;
typedef vector<pair<int, int> > vpii;
typedef vector<pair<ll, ll> > vpll;
const ll mod = 1e9 + 7;
//const ll mod = 998244353;
const double pi = acos(-1.0);
inline ll qmi (ll a, ll b) {
ll ans = 1;
while (b) {
if (b & 1) ans = ans * a%mod;
a = a * a %mod;
b >>= 1;
}
return ans;
}
inline int read () {
int x = 0, f = 0;
char ch = getchar();
while (!isdigit(ch)) f |= (ch=='-'),ch= getchar();
while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
return f?-x:x;
}
template<typename T> void print(T x) {
if (x < 0) putchar('-'), x = -x;
if (x >= 10) print(x/10);
putchar(x % 10 + '0');
}
inline ll sub (ll a, ll b) {
return ((a - b ) %mod + mod) %mod;
}
inline ll add (ll a, ll b) {
return (a + b) %mod;
}
inline ll inv (ll a) {
return qmi(a, mod - 2);
}
const int p = 20010905;
void solve() {
string s;
cin >> s;
int n =s.size();
s= " " + s;
int dp[100006]= {0};
dp[0] = 1;
string t ="iloveyou";
for (int i =1; i<= n; i ++) {
char x = tolower(s[i]);
if (x == 'i')
{
dp[1] ++;
}
if (x == 'l') {
dp[2] = (dp[2] + dp[1])%p;
}
if (x == 'o') {
dp[3] = (dp[2] + dp[3])%p;
}
if (x == 'v') {
dp[4] = (dp[4] + dp[3])%p;
}
if( x == 'e') {
dp[5]= (dp[4] + dp[5])%p;
}
if (x == 'y') {
dp[6] = (dp[6] + dp[5]) %p;
}
if (x== 'o') {
dp[7] = (dp[7] + dp[6])%p;
}
if (x == 'u') {
dp[8] = (dp[8] + dp[7])%p;
}
}
cout << dp[8] << endl;
}
int main () {
// ios::sync_with_stdio(0),cin.tie(0), cout.tie(0);
int t;
t =1;
//cin >> t;
while (t --) solve();
return 0;
}
dp[2]有多少个il取决于之气那有多少个dp[1]以及,其他类似的