初步模型，并没有实现换教练的。
import copy
class student():
def __init__(self,studentID,isAgent,leftNumsOfCourse,coach2id,coach3id):
self.studentID = studentID
self.isAgent = isAgent
self.leftNumsOfCourse = leftNumsOfCourse
self.coach2id = coach2id
self.coach3id = coach3id
def minusLeftNumsOfCourse(self,num):
self.leftNumsOfCourse = self.leftNumsOfCourse - num
def addLeftNumsOfCourse(self,num):
self.leftNumsOfCourse = self.leftNumsOfCourse + num
#测试建立学生
student1 = student('u201010187',0,23,'c232','c432')
#print(student1.leftNumsOfCourse)
student1.minusLeftNumsOfCourse(3)
#print(student1.leftNumsOfCourse)
class coach():
def __init__(self,coachid,teamID,coursesid,askForWeek):
self.coachid = coachid
self.teamID = teamID
self.coursesid = coursesid #list
self.askForWeek = askForWeek #list
def isAbleToWork(self,day):
self.askForWeek.append(day)
coach1 = coach('c2232','e33',[2,0,3],[])
#print(coach1.coursesid,coach1.askForWeek)
coach1.isAbleToWork('friday')
#print(coach1.askForWeek)
class schedule():
def __init__(self,totalSchedule=[],query={}):
# self.coachid = coachid
self.totalSchedule = totalSchedule
self.query =query #表索引字典
def createBlankSchedule(self,numsOfCourseOneDay=17): #创建一个新空的一个周期的空表
daySchedule = [0 for i in range(numsOfCourseOneDay)]
weekSchedule = [copy.deepcopy(daySchedule) for i in range(7)]
return weekSchedule
def addCoachSchedule(self,coach,coachSchedule):#添加一个教练表到总教练表中
# print(type(coach),coach.coachid)
coachSchedule = copy.deepcopy(coachSchedule)
numOfCoach = len(self.totalSchedule)
self.query['%s'%coach.coachid] = numOfCoach #建立索引
self.totalSchedule.append(coachSchedule)
def scrapeSchedule(self,son_scheduleIndex=[]):
#son_scheduleIndex = ['张三','李四','王五']
#则返回的是张三李四王五教练的课表
res = []
newQuery ={}
for coachID in son_scheduleIndex:
index = self.query[coachID]
numOfCoach = len(newQuery)
newQuery[coachID] = numOfCoach
res.append(self.totalSchedule[index])
return res,newQuery
def isCoachScheduleFull(self,coachname):
coachindex = self.query(coachname)
coachSchedule = self.totalSchedule[coachindex] #得到这个表
for i in range(7):
for j in range(17):
if coachSchedule[i][j] ==0:
return False
return True
def searchContinuousNumsOfCourse(self,coachname,day):
coachindex = self.query(coachname)
coachSchedule = self.totalSchedule[coachindex]
dayslice = coachSchedule[day]
res = []
for i in range(17):
if dayslice[i]==0:
res.append(i)
return res #输出的是[1,2,4,5,6,10,11,12,13,14...]
def getScheduleOfCoach(self,coachname): #coachname就是coachid
coachindex = self.query[coachname]
coachSchedule = self.totalSchedule[coachindex] #得到这个表
return coachSchedule
def changeScheduleOfCourse(self,coachname,day,newslice):
coachindex = self.query[coachname]
print('要改变的coach在教练表中的索引是:',coachindex)
# print('教练的某一天的表：',self.totalSchedule[coachindex][day])
self.totalSchedule[coachindex][day] = newslice
# print(self.totalSchedule)
'''每个学员每天的上课数有下限，比如2，每个学员每个上课有上限，比如5
'''
def canSatisfyRequirement12(dayslice):
count = 0
for i in range(17):
if i ==0:
count =1
continue
if dayslice[i] ==dayslice[i-1]:
count += 1
elif count <2:
return False
elif count >5:
return False
else:
count = 1
return True
'''外地学员的开始和结束课节有限制,我们令限制为Beginninglimit,Endinglimit
'''
def canSatisfyRequirement34(dayslice,student,Beginninglimit,Endinglimit):
for i in range(Beginninglimit):
if dayslice[i] == student.studentID:
return False
for j in range(Endinglimit,17):
if dayslice[j] == student.studentID:
return False
return True
#schedule1 = schedule()
#print(schedule1.createBlankSchedule(17))
#def fitcoaches(student,totalschedule):
# coachID = student.coach2id
# '''得到这个教练的教练组，这个教练组的所有教练，是一个list
# '''
#teamCoach = ['张三','李四','王五']
#scrapeSchedule = totalschedule.scrapeSchedule(teamCoach)
# return student,scrapeSchedule
'''模拟排课的，输出是模拟排出的课，满足条件才会输出
1,第一步判断是不是拆玩后学生的课表满足，要判断是不是超出了学生的接受范围
2，检查填进去的slice是不是满足要求，逐个检测，报错就不行的,如果可以的话，就要写进入表了
2.x检查临时表是不是时间段冲突，这需要定义一个函数
'''
def choice(student,schedule,coachname,day,studentArrangedSchedule):
numsOfCourse = [5,4,3,2]
slice1 = schedule.getScheduleOfCoach(coachname)[day]
# print('+++no.1+++')
# print('进入循环',slice1)
preparedslice =[]
for num in numsOfCourse:
# print('++++++no.%s+++++++'%num)
# print(slice1)
if num>student.leftNumsOfCourse:
continue #循环进入下一个
student.minusLeftNumsOfCourse(num) #修改进行判断
if not isSuitableToStudent(student):
student.addLeftNumsOfCourse(num)
continue
student.addLeftNumsOfCourse(num) #修改回来
#2的检测
preparedslice = fullslice(slice1,num,student)
if not canSatisfyRequirement12(preparedslice):
# print(slice1)
print('没有满足条件12......')
continue
if student.isAgent ==1:
if not canSatisfyRequirement34(preparedslice,student,1,1):
print('没有满足条件34.......')
continue
if isRepeat(studentArrangedSchedule,day,preparedslice):
print('没有满足条件，跟已知学生课程时间冲突')
continue
#如果上面的条件都满足，就把这个数据写到schedule中，也就是原始表中改变slice1
#学生的信息也改变，比如课时数
'''这里还缺少一个维护学生上课是不是重复的表，考虑到学生是一个个进去选课的，所以这个可以用
一个@@@@临时表@@@@维护，当学生选择上某课了，那么这个临时表就得更新
'''
schedule.changeScheduleOfCourse(coachname,day,preparedslice)
student.minusLeftNumsOfCourse(num)
print('更新前的表是:',studentArrangedSchedule)
updateSchedule(studentArrangedSchedule,day,preparedslice)
print('更新后的表是:',studentArrangedSchedule)
return True
break
# print("this slice is suitable")
# print(preparedslice)
return False
'''填完课表后，学生的剩余课时数不能为1
'''
def isSuitableToStudent(student):
if student.leftNumsOfCourse ==1:
return False
else:
return True
'''个人的课程是不是重复
schedule1----个人的历史课表
slice1----要检测的某天课程
'''
numsOfCourseOneDay =17
daySchedule = [0 for i in range(numsOfCourseOneDay)]
weekSchedule = [copy.deepcopy(daySchedule) for i in range(7)]
studentSchedule1 = weekSchedule
def isRepeat(studentSchedule1,day,slice1):
for i in range(len(slice1)): #追个检查是不是有重复安排的
if (slice1[i] != 0 and studentSchedule1[day][i] !=0):
return True
return False
def updateSchedule(studentSchedule1,day,slice1):
for i in range(len(slice1)):
if slice1[i] !=0:
studentSchedule1[day][i] = 1
'''
排列出一些位置选择
1,以学员角度，还是以课程为角度。
。。。。以课程的话，选择2,3,5优先选择多的，也就是5的，先检测5，然后检测3，再检测2
。。。。函数f(参数1，参数2,参数3)
参数1，slice
参数2，填的课，把0填成2或3或5
参数3，学生对象
。。。。返回的是排好的slice1，或者返回0，表示本身课不行的
'''
def fullslice(slice1,numOfCourse,student):
slice2 = copy.deepcopy(slice1)
for i in range(17):
if slice2[i]==0:
slice2[i]=student.studentID
numOfCourse = numOfCourse-1
if numOfCourse ==0:
break
if numOfCourse ==0:
return slice2
else:
return 0
schedule1 = schedule()
#print(schedule1.totalSchedule)
newtable = schedule1.createBlankSchedule(17)
coach1 = coach('c102','i234',1,[])
#print(coach1.teamID)
schedule1.addCoachSchedule(coach1,newtable)
#print(schedule1.totalSchedule)
coach2 = coach('c101','i234',1,[])
newtable = schedule1.createBlankSchedule(17)
schedule1.addCoachSchedule(coach2,newtable)
schedule1.changeScheduleOfCourse('c102',2,[2,2,1,1,0,0,1,1,1,0,0,0,5,5,0,0,0])
c = schedule1.totalSchedule
print('原始表:',schedule1.totalSchedule)
#print(schedule1.totalSchedule)
#print(schedule1.query)
#创建几个学生 studentID,isAgent,leftNumsOfCourse,coach2id,coach3id
student1 = student('s001',0,15,'c102','c232')
student2 = student('s002',0,3,'c102','c232')
for i in range(7):
print('教练的第%s天'%i)
choice(student1,schedule1,'c102',i,studentSchedule1)
print('学生剩余课数：',student1.leftNumsOfCourse)
if student1.leftNumsOfCourse <2:
break
print('后来表：',schedule1.totalSchedule)
本文章为转载内容，我们尊重原作者对文章享有的著作权。如有内容错误或侵权问题，欢迎原作者联系我们进行内容更正或删除文章。
