Search a 2D Matrix
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
Given target = 3
, return true
.
class Solution {
public:
bool searchMatrix(vector<vector<int> > &matrix, int target) {
int m,n,i,j;
m=matrix.size();
n=matrix[0].size();
i=0;j=n-1;
while(i<m&&j>=0)
{
if(matrix[i][j]==target)
{
return true;
}
else if(matrix[i][j]>target)
{
j--;
}
else
i++;
}
return false;
}
};