题目:啤酒2元一瓶,4个瓶盖换一瓶,2个瓶子换一瓶,问10元钱能喝几瓶?
把生活中的事情转换成代码,我们首先要做的是找出事情的规律:
喝酒产生瓶盖和瓶子,瓶盖和瓶子又能换酒,酒又产生瓶盖和瓶子,如此不断循环,那么就很容易让人想到递归。只要对细节稍加控制,就可以完成计算了。
代码如下:
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
count = 0
surplus_bottleTop = 0
surplus_bottle = 0
def drinkAndSurplus(bottleTop, bottle):
global count,surplus_bottleTop,surplus_bottle
beers = 0
beers += bottleTop//4
beers += bottle//2
count += beers
bottleTop = bottleTop%4 + beers
bottle = bottle%2 + beers
print('本次喝了%d瓶,剩余瓶盖%d个,剩余瓶子%d个'%(beers, bottleTop, bottle))
if(bottleTop//4 > 0 or bottle//2 > 0):
drinkAndSurplus(bottleTop, bottle)
else:
surplus_bottleTop = bottleTop
surplus_bottle = bottle
if __name__ == '__main__':
money = 10
count, surplus_bottleTop, surplus_bottle = money//2, money//2, money//2
print('总共%d元钱,本次喝酒%d瓶,剩余瓶盖%d个,剩余瓶子%d个'%(money,count,count,count))
drinkAndSurplus(surplus_bottleTop, surplus_bottle)
print('总共喝了%d瓶,剩余瓶盖%d个,剩余瓶子%d个'%(count,surplus_bottleTop,surplus_bottle))
执行结果如下:
python新手,大神勿喷!