只要算出两者距离减去半径之和,就变成平面图了

/* ***********************************************
Author :PeterBishop
Created Time :Sat 02 Mar 2019 17:18:28 CST
File Name :t.cpp
Origin :P O J 2031
************************************************ */

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>

using namespace std;
const int MAXN=101;
double cost[MAXN][MAXN];
const double INF=10000;
bool vis[MAXN];
double lowc[MAXN];
struct node{
double x;
double y;
double z;
double r;
}p[MAXN];
double dis(node a,node b){
double d=(a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)+(a.z-b.z)*(a.z-b.z);
d=sqrt(d)-a.r-b.r;
if(d<0)
d=0;
return d;
}
double prim(int n){
memset(vis,false,sizeof(vis));
double ans=0;
for(int i=0;i<n;i++)
lowc[i]=cost[0][i];
vis[0]=true;
for(int i=1;i<n;i++){
int p;
double minc=INF;
for(int j=1;j<n;j++)
if(!vis[j]&&minc>lowc[j]){
p=j;
minc=lowc[j];
}
vis[p]=true;
ans+=minc;
if(minc==INF)
return -1;
for(int j=0;j<n;j++)
if(!vis[j]&&lowc[j]>cost[p][j])
lowc[j]=cost[p][j];
}
return ans;
}
int main()
{
//freopen("out.txt","w",stdout);
freopen("in.txt","r",stdin);
int n;
while(cin>>n){
if(n==0)
break;
for(int i=0;i<MAXN;i++)
for(int j=0;j<MAXN;j++)
cost[i][j]=i==j?0:INF;
for(int i=0;i<n;i++){
cin>>p[i].x>>p[i].y>>p[i].z>>p[i].r;
}

for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
double d=dis(p[i],p[j]);
cost[i][j]=cost[j][i]=d;
}
}
printf("%.3f\n",prim(n));
}
return 0;
}