小关键:要用while 输入; 把已经修好路的两个村子之间的距离改为0即可


#include<iostream>
#include<stdlib.h>
#include<math.h>
#include<stdio.h>
#include<algorithm>
#include<queue>
#include<string.h>
#include<stack>
#include<math.h>
#include<stdlib.h>
#include<list>
#include<vector>

using namespace std;


#define N 100

int map[N][N];
int hi[N];
bool vist[N];
int ans;

int main()
{
    int i,j,k;
    int n;
    while (cin>>n)
    {
    for (i=0;i<n;i++)
        for (j=0;j<n;j++)
            cin>>map[i][j];
    int m;
    cin>>m;
    while (m--)
    {
        cin>>i>>j;
        i--;
        j--;
        map[i][j]=map[j][i]=0;
    }
    memset(vist,false,sizeof(vist));
    vist[0]=true;
    for (i=0;i<n;i++)
        hi[i]=map[0][i];
    k=n-1;
    ans=0;
    while (k--)
    {
        int big=100000000;
        for (i=1;i<n;i++)
        {
            if (!vist[i]&&hi[i]<big)
                big=hi[i],j=i;
        }
        ans+=big;
        vist[j]=true;
        for (i=1;i<n;i++)
            if (!vist[i]&&hi[i]>map[i][j])
                hi[i]=map[i][j];
    }
    cout<<ans<<endl;
    }
}





Constructing Roads


Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6633    Accepted Submission(s): 2443



Problem Description


There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and B, or there exists a village C such that there is a road between A and C, and C and B are connected.

We know that there are already some roads between some villages and your job is the build some roads such that all the villages are connect and the length of all the roads built is minimum.


 



Input


The first line is an integer N (3 <= N <= 100), which is the number of villages. Then come N lines, the i-th of which contains N integers, and the j-th of these N integers is the distance (the distance should be an integer within [1, 1000]) between village i and village j.

Then there is an integer Q (0 <= Q <= N * (N + 1) / 2). Then come Q lines, each line contains two integers a and b (1 <= a < b <= N), which means the road between village a and village b has been built.


 



Output


You should output a line contains an integer, which is the length of all the roads to be built such that all the villages are connected, and this value is minimum.


 



Sample Input


3 0 990 692 990 0 179 692 179 0 1 1 2


 



Sample Output


179


 



Source


kicc


 



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