assume cs:code code segment start: mov bx,0 mov cx,8 s: mov ax,a mov ds,ax mov dx,ds:[bx] mov ax,b mov ds,ax mov ds:[bx],dx add bx,2 loop s mov ax,4c00h int 21h code ends a segment d
Copyright © 2005-2024 51CTO.COM 版权所有 京ICP证060544号