纯小学数学应用题。。。。
A snail is at the bottom of a 6-foot well and wants to climb to the top. The snail can climb 3 feet while the sun is up, but slides down 1
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2023-04-13 22:56:26
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The Snail A snail is at the bottom of a 6-foot well and wants to climb to the top. The she sna
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2023-04-21 09:32:17
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Snail’s trouble Problem Description Once upon a time, there was a poor snail. Every day, it tried very hard to crawl forward, while there was a keeper
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2017-02-17 10:33:00
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题目大意：蜗牛从井底往上爬，井高H米，它每天能爬U米，每天夜里下滑D，每天它疲劳，每天能爬的jvli减少第一个天能爬的距离百分
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2021-12-01 16:03:18
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题目地址：点击打开链接AC代码：#includeint main(){ double h,u,d,f,sum,down; int day,flag; while(scanf("%lf%lf%lf%lf",&h,&u,&d,&f) && h) { flag = 1; day = 0; sum = 0; f = f / 100; down = f * u;
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2022-08-04 09:05:14
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题意：
一直蜗牛想爬出深度度为h的井，白天向上爬u米，晚上下降d米，还有一个就是第二天向上爬的距离为减少F%，第三天又减少F%，u至少为零，不会变成负数。当蜗牛爬出井口或者滑到井底就输出当时的天数。
注意：刚好到井口或者刚好到井底是不算的。
思路：
模拟蜗牛的爬行。
#include
#include
using namespace std;
int main()
{
double h
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2022-10-19 16:14:03
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The SnailA snail is at the bottom of a 6-foot well and wants to climb to the top. The snail can climb 3 feet while the sun is up, but slides down 1 foot at night while sleeping.
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2013-08-16 18:04:00
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蜗牛爬井问题 不同的这次加入了疲劳度 每一天...
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2016-06-05 02:53:00
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The SnailTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/3
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2022-08-30 15:15:55
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573 - The SnailTime limit: 3.000 secondshttp://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=99&page=show_problem&problem=514A snail is at the bottom of a 6-foot wel
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2023-04-12 05:53:14
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The SnailTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3126 Accepted Submission(s): 2249Problem DescriptionA snail is at the bo
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2023-02-20 10:23:33
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Sally Snail likes to stroll on a N x N square grid (1 <n <= 120). She always starts in the upper left corner of the grid. The grid has empty squares (
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2017-02-09 18:55:00
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#include<stdio.h>#include<math.h>const double esp=1.0e-10;double a[400];int main(){ int k; int i; a[0]=0; for(i=1;i<400;i++) a[i]=a[i-1]+1.0/i; int b[11]={441,710,1230,2336,4983,12367,37568,150661, 898515,9717617,272400600}; while(scanf("%d",&k)!=EOF) //for(k=5;k<101;
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2013-04-26 14:43:00
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简单看一下UITextField的属性 - (void)createTextField{ UITextField * textField = [[UITextField alloc] initWithFrame:CGRectMake(40, 40, 240, 40)]; //设置UITextFiel
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2017-04-26 16:43:00
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嘟嘟嘟 一道很水的爆搜题，然后我调了近40分钟…… 错误：输入数据最好用cin，因为数字可能不止一位，所以用scanf后，单纯的c[0]为字母，c[1]数字………………………… 1 #include<cstdio> 2 #include<iostream> 3 #include<cmath> 4 #
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2021-05-29 19:14:45
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Problem Description
A snail is at the
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2022-08-11 16:48:54
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本篇概要：1. 异步发送邮件工具原理；2. 安装 Redis 服务；3. 安装 PHP 的 Redis 扩展；4. 安装 Yii2 的 Redis 插件； 1. 异步发送邮件工具原理；现有邮件发送系统的实现：用户点击注册连接邮箱服务器将注册信息发送给邮箱服务器邮箱服务器返回结果到本地 WEB 服务器不可控因素网络问题：如果网络比较慢，连接邮箱服务器的时候，响应比较慢，用户体验差解决方案用户注册后
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2023-10-11 09:07:55
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