题目传送门//简单dfs加步数记录#include<cstdio>#include<cstring>#include<iostream>using namespace std;char Map[12][12];int vis[12][12];int ro,co,lo;int cnt;void dfs(int a,int b,int step);int m
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2022-04-20 10:00:41
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Robot MotionTime Limit:1000MSMemory Limit:10000KTotal S
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2015-10-18 12:57:00
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Description
A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are
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2023-04-13 22:48:12
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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3266 Accepted Submission(s): 1519
Problem Description
A ro
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2023-02-24 10:14:30
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题目链接：POJ 1573
Robot Motion 一个小模拟，非常easy，依照提示一步步走就是了 #include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cstring> u
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2017-04-25 16:23:00
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Robot MotionTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7974Accepted Submission(s): 3685Proble...
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2015-07-01 22:41:00
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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3266 Accepted Submission(s): 1519Problem DescriptionA robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a gri
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2012-04-25 16:21:00
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Robot MotionTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (J
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2022-03-17 16:36:49
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Robot Motion
Memory Limit: 10000K
Total Submissions: 10221
Accepted: 4978
Description
A robot has been programmed to follow the instructions in
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2023-04-21 01:24:18
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char map[12][12];
int visit[12][12];
int main()
{
char
p,local;
int
a,b,c,M,N,sum;
while(1)
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2022-08-23 08:18:35
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题意：给你一个棋盘，上面的字母代表机器人要走的方向。假设机器人能走出这个棋盘，则输出机器人所走的步数，否则输出该机器人在走向无限循环前所走的步数。及无限循环所要走的格子数
思路：直接模拟，没有思路（大神能够多考虑些思路）
AC代码：
#include<stdio.h>
#include<string.h>
char str[12][12];
int flag[12][
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2017-08-06 17:23:00
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#include <iostream>#include <queue>#include <vector>#include <algorithm>#include <stack>using
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2023-02-22 08:03:22
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Description A robot has been programmed to follow the instructions in its path. Instructions nstructions are
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2022-08-10 10:28:58
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http://poj.org/problem?id=1573 1 #include 2 #include 3 #include 4 #define maxn 500 5 using namespace std; 6 char g[maxn][maxn]; 7 int r,l,st; 8 int vis[maxn][maxn]; 9 int main()10 {11 while(scanf("%d%d%d",&r,&l,&st)!=EOF)12 {13 if(r==0&&l==0&&st==0) break;14 for
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2014-01-18 08:34:00
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Problem Description
A robot has bee
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2022-08-12 09:54:54
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题目地址：http://poj.org/problem?id=1573 1 /* 2 题意：给定地图和起始位置，robot(上下左右)一步一步去走，问走出地图的步数 3 如果是死循环，输出走进死循环之前的步数和死循环的步数 4 模拟题：used记录走过的点，因...
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2015-03-27 17:52:00
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Robot MotionTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 13107 Acc
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2022-11-20 14:20:03
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很水的模拟题，把-号写成了=号，找了一个小时我也是醉了，但发现自己比原来还是进步了#include#include#includeusing namespace std;const int maxn = 100;char map[maxn][maxn];int vis[maxn][maxn];int main(){ int m,n,x; while(scanf(
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2022-08-05 16:40:19
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