[题目描述]
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
[解题思路]
因为链表已经排过序了,所以操作就非常简单,直接遍历,遇到值一样的就删掉,直到不一样就跨过。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *deleteDuplicates(ListNode *head) { // Start typing your C/C++ solution below // DO NOT write int main() function ListNode *p = head; ListNode *q = p; while (p) { q = p->next; if (q && (q->val == p->val)) { p->next = q->next; delete q; } else p = p->next; } return head; } };
[源代码]
https://github.com/rangercyh/leetcode/blob/master/Remove%20Duplicates%20from%20Sorted%20List