在二维平面上计算出两个由直线构成的矩形重叠后形成的总面积。

每个矩形由其左下顶点和右上顶点坐标表示，如图所示。

LeetCode 223. 矩形面积_编程题目

示例:

输入: -3, 0, 3, 4, 0, -1, 9, 2
输出: 45

说明: 假设矩形面积不会超出 int 的范围。

 

class Solution {
public:
    int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int overlap[4] = {
            max(A, E),
            max(B, F),
            min(C, G),
            min(D, H)
        };
        int area1 = (C - A) * (D - B);
        int area2 = (G - E) * (H - F);
        int area_intxn = (overlap[2] > overlap[0] && overlap[3] > overlap[1]) ? (overlap[2] - overlap[0]) * (overlap[3] - overlap[1]) : 0;
        return area1 - area_intxn + area2;
    }
};