题目一

写一个完整的8086汇编语言程序：键盘输入10个数据，存入一维数组中（字），并找出数组中最大值显示在屏幕上。

源码
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;Program:;Author:Nonoas;Date:20191106
.386.MODEL FLAT
ExitProcess PROTO NEAR32 stdcall, dwExitCode:DWORD
INCLUDE io.h            ; header file for input/output
cr      EQU     0dh     ; carriage return characterLf      EQU     0ah     ; line feed
.STACK  4096            ; reserve 4096-byte stack
.DATA                   ; reserve storage for data
prompt1 byte ".Enter a number of Array:",0prompt2 byte cr,lf,"The max number is:",0number byte 20 dup (?)maxNum byte 20 dup (?)nbrArrary WORD 100 dup (?)count word ?
.CODE                           ; start of main program code_start:    mov ecx,10    mov count,1    mov dx,count    lea ebx,nbrArraryforCount:    itoa count,dx    output count    output prompt1    input number,20    atoi number    mov [ebx],ax    add dx,1    add ebx,2loop forCount
    mov ecx,9    lea ebx,nbrArrary    mov ax,[ebx]forCount1:    add ebx,2    cmp [ebx],ax    jb endJudge    mov ax,[ebx]endJudge:    loop forCount1
    output prompt2    itoa maxNum,ax    output maxNum

        INVOKE  ExitProcess, 0  ; exit with return code 0PUBLIC _start                   ; make entry point public
END                             ; end of source code

 

 

 

题目二

写一个完整的8086汇编语言程序：键盘输入10个数据，存入一维数组中（双字），并找出数组中最小的偶数显示在屏幕上，若没有偶数则显示“没有偶数！”。

源码
  •  
;Program:;Author:Nonoas;Date:20191106
.386.MODEL FLAT
ExitProcess PROTO NEAR32 stdcall, dwExitCode:DWORD
INCLUDE io.h            ; header file for input/output
cr      EQU     0dh     ; carriage return characterLf      EQU     0ah     ; line feed
.STACK  4096            ; reserve 4096-byte stack
.DATA                   ; reserve storage for dataprompt1 byte ".Enter a number of Array:",0prompt2 byte cr,lf,"The min even number is:",0prompt3 byte cr,lf,"There is no even number",0number byte 20 dup (?)minNum byte 20 dup (?)nbrArrary DWORD 100 dup (?)count DWORD ?
.CODE                           ; start of main program code_start:    mov ecx,10    mov count,1    mov edx,count    lea ebx,nbrArraryforCount:    dtoa count,edx    output count    output prompt1    input number,20    atod number    mov [ebx],eax    add edx,1    add ebx,4loop forCount
    mov ecx,10          ;judge have even    lea ebx,nbrArraryFIND:    mov al,[ebx]    test al,01H        ;if isodd, jump to next    jnz NEXT    mov edx,[ebx]       ;if iseven, save it    jmp FINDENDNEXT:    add ebx,4loop FIND
    mov edx,0FFFFH    jmp EXITFINDEND:           ;if find a even , jump here
    mov ecx,10           ;find the min even    lea ebx,nbrArraryFIND2:    mov al,[ebx]    test al,01H    jnz NEXT2        ;if is odd, jump to next    cmp edx,[ebx]    jb NEXT2    mov edx,[ebx]NEXT2:    add ebx,4    loop FIND2
    output prompt2    dtoa minNum,edx    output minNum    jmp endall
EXIT:    output prompt3    jmp endall
endall:
        INVOKE  ExitProcess, 0  ; exit with return code 0PUBLIC _start                   ; make entry point public
END                             ; end of source code

 

 

【8086汇编(实验)】循环结构_8086汇编