CUBE

功能描述:

注意:

 

ROLLUP

功能描述:

注意:

 

如果是ROLLUP(A, B, C)的话,GROUP BY顺序

(A、B、C)

(A、B)

(A)

最后对全表进行GROUP BY操作。

如果是GROUP BY CUBE(A, B, C),GROUP BY顺序

(A、B、C)

(A、B)

(A、C)

(A),

(B、C)

(B)

(C),

最后对全表进行GROUP BY操作。

代码如下:

CREATE TABLE studentscore
(
student_name varchar2(20),
subjects varchar2(20),
score number
)
INSERT INTO studentscore VALUES('WBQ','ENGLISH',90);
INSERT INTO studentscore VALUES('WBQ','MATHS',95);
INSERT INTO studentscore VALUES('WBQ','CHINESE',88);
INSERT INTO studentscore VALUES('CZH','ENGLISH',80);
INSERT INTO studentscore VALUES('CZH','MATHS',90);
INSERT INTO studentscore VALUES('CZH','HISTORY',92);
INSERT INTO studentscore VALUES('CB','POLITICS',70);
INSERT INTO studentscore VALUES('CB','HISTORY',75);
INSERT INTO studentscore VALUES('LDH','POLITICS',80);
INSERT INTO studentscore VALUES('LDH','CHINESE',90);
INSERT INTO studentscore VALUES('LDH','HISTORY',95);

Oracle分析函数八——CUBE,ROLLUP_sql

常用代码如下:

SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects);
等同于以下标准SQL
SELECT NULL,subjects,SUM(score)
FROM studentscore
GROUP BY subjects
UNION
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects

SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects);

SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects


SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;

SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1,2;

SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1;

SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1;

SELECT
grouping(student_name),
grouping(subjects),
CASE WHEN grouping(student_name)=0 AND grouping(subjects)=1 THEN '学生成绩合计'
WHEN grouping(student_name)=1 AND grouping(subjects)=0 THEN '课目成绩合计'
WHEN grouping(student_name)=1 AND grouping(subjects)=1 THEN '总 计'
ELSE ''
END SUMMARY,
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;

Oracle分析函数八——CUBE,ROLLUP_常用代码_02