Oracle 分析函数——CUBE , ROLLUP
CUBE
功能描述:
注意:
 
ROLLUP
功能描述:
注意:
 
如果是 ROLLUP(A, B, C) 的话, GROUP BY 顺序
(A 、 B 、 C)
(A 、 B)
(A)
最后对全表进行 GROUP BY 操作。
如果是 GROUP BY CUBE(A, B, C) , GROUP BY 顺序
(A 、 B 、 C)
(A 、 B)
(A 、 C)
(A) ,
(B 、 C)
(B)
(C) ,
最后对全表进行 GROUP BY 操作。
 
CREATE TABLE studentscore
(
 student_name varchar2(20),
 subjects varchar2(20),
 score number
)
INSERT INTO studentscore VALUES('WBQ','ENGLISH',90);
INSERT INTO studentscore VALUES('WBQ','MATHS',95);
INSERT INTO studentscore VALUES('WBQ','CHINESE',88);
INSERT INTO studentscore VALUES('CZH','ENGLISH',80);
INSERT INTO studentscore VALUES('CZH','MATHS',90);
INSERT INTO studentscore VALUES('CZH','HISTORY',92);
INSERT INTO studentscore VALUES('CB','POLITICS',70);
INSERT INTO studentscore VALUES('CB','HISTORY',75);
INSERT INTO studentscore VALUES('LDH','POLITICS',80);
INSERT INTO studentscore VALUES('LDH','CHINESE',90);
INSERT INTO studentscore VALUES('LDH','HISTORY',95);
Oracle分析函数八——CUBE,ROLLUP_ROLLUP
 
SELECT
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY CUBE(student_name,subjects);
等同于以下标准 SQL
SELECT NULL,subjects,SUM(score)
 FROM studentscore
 GROUP BY subjects
 UNION
SELECT student_name,NULL,SUM(score)
 FROM studentscore
 GROUP BY student_name
 UNION
SELECT NULL,NULL,SUM(score)
 FROM studentscore
 UNION
SELECT student_name,subjects,SUM(score)
 FROM studentscore
 GROUP BY student_name,subjects
 
SELECT
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY ROLLUP(student_name,subjects);
 
SELECT student_name,NULL,SUM(score)
 FROM studentscore
 GROUP BY student_name
 UNION
SELECT NULL,NULL,SUM(score)
 FROM studentscore
 UNION
SELECT student_name,subjects,SUM(score)
 FROM studentscore
 GROUP BY student_name,subjects
 
 
SELECT
 grouping(student_name),
 grouping(subjects), 
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY CUBE(student_name,subjects)
 ORDER BY 1,2;
 
SELECT
 grouping(student_name),
 grouping(subjects), 
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY ROLLUP(student_name,subjects)
 ORDER BY 1,2;
 
SELECT
 grouping_id(student_name,subjects),  
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY CUBE(student_name,subjects)
 ORDER BY 1;
 
SELECT
 grouping_id(student_name,subjects),  
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY ROLLUP(student_name,subjects)
 ORDER BY 1;
 
SELECT
 grouping(student_name),
 grouping(subjects),
 CASE WHEN grouping(student_name)=0 AND grouping(subjects)=1 THEN ' 学生成绩合计 '
      WHEN grouping(student_name)=1 AND grouping(subjects)=0 THEN ' 课目成绩合计 '
      WHEN grouping(student_name)=1 AND grouping(subjects)=1 THEN ' 总                 计 '
      ELSE ''
 END SUMMARY,
 student_name,
 subjects,
 sum(score)
 FROM studentscore
 GROUP BY CUBE(student_name,subjects)
 ORDER BY 1,2;