# include<stdio.h>
# include<string.h>

int main()
{
  int n=0;
  char a[5];
  while(~scanf("%s",a))
  {
    printf("Case %d: ",++n);
    if(strcmp(a,"I")==0)
      printf("1");
    else if(strcmp(a,"II")==0)
      printf("2");
    else if(strcmp(a,"III")==0)
      printf("3");
    else if(strcmp(a,"IV")==0)
      printf("4");
    else if(strcmp(a,"V")==0)
      printf("5");
    else if(strcmp(a,"VI")==0)
      printf("6");
    else if(strcmp(a,"VII")==0)
      printf("7");
    else if(strcmp(a,"VIII")==0)
      printf("8");
    else if(strcmp(a,"IX")==0)
      printf("9");
    else if(strcmp(a,"X")==0)
      printf("10");
    else if(strcmp(a,"XI")==0)
      printf("11");
    else if(strcmp(a,"XII")==0)
      printf("12");
    printf("\n");
  }


  return 0;
}

时间限制： 1000 ms  |  内存限制： 65535 KB

难度： 1

描述

Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest. They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so attractive that Mr. B would always like to take a walk outside for a while after breakfast. However, Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot understand such kind of numbers. Can you translate for him?


输入

Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.

输出

For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.

样例输入 

I
II
III
IV
V
VI
VII
VIII
IX
X
XI
XII

样例输出

Case 1: 1
Case 2: 2
Case 3: 3
Case 4: 4
Case 5: 5
Case 6: 6
Case 7: 7
Case 8: 8
Case 9: 9
Case 10: 10
Case 11: 11
Case 12: 12
# include<stdio.h>
# include<string.h>

int main()
{
  int n=0;
  char a[5];
  while(~scanf("%s",a))
  {
    printf("Case %d: ",++n);
    if(strcmp(a,"I")==0)
      printf("1");
    else if(strcmp(a,"II")==0)
      printf("2");
    else if(strcmp(a,"III")==0)
      printf("3");
    else if(strcmp(a,"IV")==0)
      printf("4");
    else if(strcmp(a,"V")==0)
      printf("5");
    else if(strcmp(a,"VI")==0)
      printf("6");
    else if(strcmp(a,"VII")==0)
      printf("7");
    else if(strcmp(a,"VIII")==0)
      printf("8");
    else if(strcmp(a,"IX")==0)
      printf("9");
    else if(strcmp(a,"X")==0)
      printf("10");
    else if(strcmp(a,"XI")==0)
      printf("11");
    else if(strcmp(a,"XII")==0)
      printf("12");
    printf("\n");
  }


  return 0;
}