题目:原题链接(中等)
标签:数组
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O ( N ) | O ( 1 ) | 56ms (98%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一:
class Solution:
def longestSubarray(self, nums: List[int]) -> int:
if set(nums) == {1}:
return len(nums) - 1
ans = 0
last, now = 0, 0
for n in nums:
if n == 1:
now += 1
else:
ans = max(ans, last + now)
last = now
now = 0
ans = max(ans, last + now)
return ans
















