We can use recursive to solve, every time we can check if current situation can append ‘(’ or ‘)’. Then append it recursive. If meet left == n and right == n, store the string.
Not too many point to take care.
文章标签 系统 文章分类 JavaScript 前端开发
We can use recursive to solve, every time we can check if current situation can append ‘(’ or ‘)’. Then append it recursive. If meet left == n and right == n, store the string.
Not too many point to take care.
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