leetcode-285-Inorder Successor in BST

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zem_nezer 2023-08-23 09:10:57 博主文章分类：算法 ©著作权

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Error:
cannot solve it. Use inorder traverse need O(n).

So we use the property of BST, when meet the target p, it have two cases:

p has right subtree, first move root = root.right, then find its leftmost node
p has not right subtree, return its parent

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