【坚持每日一题10.16】三合一

三合一。描述如何只用一个数组来实现三个栈。

你应该实现push(stackNum, value)、pop(stackNum)、isEmpty(stackNum)、peek(stackNum)方法。stackNum表示栈下标，value表示压入的值。

构造函数会传入一个stackSize参数，代表每个栈的大小。

示例1:

输入：
[“TripleInOne”, “push”, “push”, “pop”, “pop”, “pop”, “isEmpty”]
[[1], [0, 1], [0, 2], [0], [0], [0], [0]]
输出：
[null, null, null, 1, -1, -1, true]
说明：当栈为空时pop, peek返回-1，当栈满时push不压入元素。
示例2:

输入：
[“TripleInOne”, “push”, “push”, “push”, “pop”, “pop”, “pop”, “peek”]
[[2], [0, 1], [0, 2], [0, 3], [0], [0], [0], [0]]
输出：
[null, null, null, null, 2, 1, -1, -1]

java代码：

class TripleInOne{
    public int[] a;
    private int stackSize;
    private int index1,index2,index3;
    public TripleInOne(int stackSize) {
        this.stackSize = stackSize;
        a = new int[stackSize * 3];
        index1 = -1;// [0,stackSize)
        index2 = stackSize - 1;//[stackSize,stackSize*2)
        index3 = stackSize * 2 - 1 ;//[stackSize*2,stackSize*3)
        for (int i = 0; i < a.length; i++) {
            a[i] = -1;
        }
    }

    public void push(int stackNum, int value) {
        if (stackNum == 0){
            if (index1+1 < stackSize){
                index1++;
                a[index1] = value;
            }else{
                return;
            }
        }
        if (stackNum == 1){
            if (index2+1 < stackSize*2){
                index2++;
                a[index2] = value;
            }else{
                return;
            }
        }
        if (stackNum == 2){
            if (index3+1 < stackSize*3){
                index3++;
                a[index3] = value;
            }
        }
    }


    public int pop(int stackNum) {
        if (stackNum == 0 && index1 >= 0){
                index1--;
                return a[index1+1];
        }
        if (stackNum == 1 && index2 >= stackSize){
                index2--;
                return a[index2+1];
        }
        if (stackNum == 2 && index3 >= stackSize*2){
                index3--;
                return a[index3+1];
        }
        return -1;
    }

    public int peek(int stackNum) {
        int result = -1;
        if (stackNum == 0 && index1 >= 0){
                result = a[index1];
        }
        if (stackNum == 1 && index2 >= stackSize){
                result = a[index2];
        }
        if (stackNum == 2 && index3 >= stackSize*2){
                result = a[index3];
        }
        return result;
    }

    public boolean isEmpty(int stackNum) {
        if (stackNum == 0 && index1 == -1){
                return true;
        }
        if (stackNum == 1 && index2 == stackSize-1){
                return true;
        }
        if (stackNum == 2 && index3 == stackSize*2-1){
                return true;
        }
        return false;
    }
}

/**
 * Your TripleInOne object will be instantiated and called as such:
 * TripleInOne obj = new TripleInOne(stackSize);
 * obj.push(stackNum,value);
 * int param_2 = obj.pop(stackNum);
 * int param_3 = obj.peek(stackNum);
 * boolean param_4 = obj.isEmpty(stackNum);
 */