题目链接:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/

题目:

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

思路:

新建一个结点保存mid值,该结点的左右子树也递归生成,这是个常用的模板

算法:

public TreeNode sortedArrayToBST(int[] nums) {
		if (nums == null || nums.length == 0) {
			return null;
		}
		return test(nums, 0, nums.length - 1);
	}

	public TreeNode test(int[] nums, int left, int right) {
		if (right < left)
			return null;
		int mid = (left + right) / 2;
		TreeNode root = new TreeNode(nums[mid]);
		root.left = test(nums, left, mid - 1);
		root.right = test(nums, mid + 1, right);
		return root;
	}