【Leetcode】Compare Version Numbers

题目链接：https://leetcode.com/problems/compare-version-numbers/

题目：

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

. character.

The . character does not represent a decimal point and is used to separate number sequences.

For instance, 2.5

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

算法：

 

1. public int compareVersion(String version1, String version2) {  
2. "\\.");  
3. "\\.");  
4. int length = Math.max(v1.length, v2.length);  
5. int vv2[] = new int[length];  
6. int vv1[] = new int[length];  
7. for (int i = 0; i < v1.length; i++) {  
8.         vv1[i] = Integer.parseInt(v1[i]);  
9.     }  
10. for (int i = 0; i < v2.length; i++) {  
11.         vv2[i] = Integer.parseInt(v2[i]);  
12.     }  
13.       
14. int flag = -1;  
15. int i = 0, j = 0;  
16. while (i < length) {  
17. if (vv1[i] > vv2[i]) {  
18. 1;  
19. break;  
20. else if (vv1[i] < vv2[j]) {  
21. 1;  
22. break;  
23. else {  
24. 0;  
25.             i++;  
26.             j++;  
27.         }  
28.     }  
29. return flag;  
30. }