d的自动域问题

​​原文​​

auto screen = executeShell(cmdLine);
auto s;//这样声明?
 //无法推导`"s"`的类型.
//从`getPath`的返回类型来看,可能是`string[]`.
//应该这样
string[] s;
...
{
    s = screen.output.findSplit("REG_SZ");
}

//但不编译.

string[] getPath(string cmdLine)
{
    auto screen = executeShell(cmdLine);

    if (screen.status != 0)
    {
        writeln(cmdLine, " failed");
    }
    else
    {
        writeln("screen.output = ", screen.output);
        auto s = screen.output.findSplit("REG_SZ");
        writeln("s[0] = ", s[0]);
        writeln("s[1] = ", s[1]);
        writeln("s[2] = ", s[2]);
    }
    return (s.split(';'));  // 未定义s
}

如何重构?
​​​executeShell​​​失败时会怎样?
​​​a​​​)这是错误;程序不应​​继续​​​.可用​​'enforce'​​(这是我的编码方式):

string[] getPath(string cmdLine)
{
    import std.exception : enforce;

    auto screen = executeShell(cmdLine);
    enforce(screen.status == 0, format!"%s failed:\n%s"(cmdLine, screen.output));
//确保
    writeln("screen.output = ", screen.output);
    //后面略....
}

​​b​​​)这不是错误;​​getPath()​​​应该返回​​空数组​​:

string[] getPath(string cmdLine)
{
    string[] result;
    auto screen = executeShell(cmdLine);

    if (screen.status != 0)
    {
        writeln(cmdLine, " failed");
        return null;  // 在此(`无效`转数组)
    }
    else
    {
        // ...
        // 现在返回s定义的.
        return (s.split(';'));
    }
}