该语法糖在jvm脚本语言Groovy/Scale已有很好的支持,Java从8.0才开始支持该特性。

 

/**
* 基础Lambda表达式
*
*/
public static void testLambda() {
String[] ss = { "hello", "world", "sun" };
List<String> list = Arrays.asList(ss);

// 接口作为回调函数,C: typdef int (*func)(int,int)
AddService func = (int a, int b) -> (a + b);
func.add(20, 21);
// 多条语句用{}包围
AddService func1 = (int a, int b) -> { System.out.println("count"); return (a + b); };
func1.add(20, 21);

// 1.遍历
// forEach
list.forEach((player) -> System.out.println(player));

// ::
list.forEach(System.out::println);

// 2.排序
Arrays.sort(ss, (String s1, String s2) -> (s1.compareTo(s2)));

// 3.线程
new Thread(() -> System.out.println(Thread.currentThread().getName() + ">Say hello")).start();
Runnable th1 = () -> System.out.println(Thread.currentThread().getName() + ">Say world");
th1.run();
}

/**
* Stream lambda
* 强大的filter条件过滤
*/
public static void testStream() {
// Programmer
List<Person> progm = new ArrayList<Person>() {
{
add(new Person("Jarrod", "Pace", "PHP programmer", "male", 34, 1550));
add(new Person("Clarette", "Cicely", "PHP programmer", "female", 23, 1200));
add(new Person("Victor", "Channing", "PHP programmer", "male", 32, 1600));
add(new Person("Tori", "Sheryl", "PHP programmer", "female", 21, 1000));
add(new Person("Osborne", "Shad", "PHP programmer", "male", 32, 1100));
add(new Person("Rosalind", "Layla", "PHP programmer", "female", 25, 1300));
add(new Person("Fraser", "Hewie", "PHP programmer", "male", 36, 1100));
add(new Person("Quinn", "Tamara", "PHP programmer", "female", 21, 1000));
add(new Person("Alvin", "Lance", "PHP programmer", "male", 38, 1600));
add(new Person("Evonne", "Shari", "PHP programmer", "female", 40, 1800));
}
};

// 定义filter
Predicate<Person> ageFilter = (p) -> (p.getAge() > 21); // age>21
Predicate<Person> salaryFilter = (p) -> (p.getSalary() > 1000); // salary>1000
Predicate<Person> genderFilter = (p) -> ("female".equals(p.getGender())); // femail

// 过滤年龄大于21岁且月薪大于$1,000以上的2名女程序员
progm.stream()
.filter(ageFilter)
.filter(salaryFilter)
.filter(genderFilter)
.limit(2) // 只取2条记录
.forEach((p) -> System.out.printf("%s %s; ", p.getFirstname(), p.getLastname()));

// 根据姓排序,将结果输出至list
List<Person> sortprogm = progm
.stream()
.sorted( (p,p2) -> (p.getFirstname().compareTo(p2.getFirstname())))
.limit(2)
.collect( Collectors.toList() );

// 过滤工资最低的程序员
Person per = progm
.stream()
.min( (p,p2) -> (p.getSalary() - p2.getSalary()) )
.get();

/// map/reduce lambda表达式不可或缺两组函数
// map --> 将姓添加至set
Set<String> set = progm
.stream()
.map(Person::getFirstname)
.collect( Collectors.toSet() );

// reduce --> 所有工资的总和
int total = progm
.stream()
.map( Person::getSalary )
.reduce( 0, (a,b) -> a+b );

// 数组最大最小值,总和,平均值等汇总
List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
IntSummaryStatistics stats = numbers
.stream()
.mapToInt((x) -> x)
.summaryStatistics();
}

 

参考链接:

​​Java lambda表达式入门​​