Mysql基础(四)

进阶5 分组查询

语法:

SELECT 分组函数,列(要求出现在 group by 的后面)

FROM 表

【where 筛选条件】

group by 分组的列表

【order by 子句】

注意:查询列表必须特殊,要求是分组函数的和group by 后出现的字段

特点:

1、分组查询中的筛选条件分为两类

数据源 位置 关键字

分组前筛选 原始表 GROUP BY 子句的前面 WHERE

分组后筛选 分组后的语句集 GROUP BY 子句的后面 HAVING

一、分组函数做条件肯定是放在Having 子句中

二、能用分组前筛选的,就优先考虑使用分组筛选

2、GROUP BY 子句支持单个字段分组,也支持多个字段分组

(多个字段之间用逗号分开没有排序要求),表达式或函数(用的较少)

3、也可以添加排序(排序放在整个分组查询的最后)

#引入案例:查询每个部门的平均工资

SELECT department_id 部门id, AVG(salary) 平均工资 FROM employees GROUP BY department_id;

#简单分组查询

#案例一:查询每个工种的最高工资

SELECT MAX(salary) 最高工资,job_id 工种 FROM employees GROUP BY job_id;

#案例二:查询每个位置上的部门个数

SELECT COUNT(*) 部门个数,location_id 位置id FROM departments GROUP BY location_id;

#添加分组前筛选条件

#案例1:查询邮箱中包含a字符的,每个部门平均工资

SELECT AVG(salary),department_id

FROM employees WHERE email LIKE '%a%'

GROUP BY department_id

#案例二:查询有奖金的每个领导手下员工的最高工资

SELECT MAX(salary),manager_id FROM employees

WHERE commission_pct IS NOT NULL

GROUP BY manager_id;

#添加分组后的筛选

#案例1:查询那个部门的员工个数 >2

SELECT department_id 部门id,COUNT(*) 个数 FROM employees

GROUP BY department_id

HAVING COUNT(*) >2 ;

#案例二:查询每个工种有奖金的员工的最该工资 > 12000 的工种编号和最高工资

SELECT MAX(salary),job_id FROM employees

WHERE commission_pct IS NOT NULL

GROUP BY job_id

HAVING MAX(salary) > 12000;

#按表达式或函数分组

#案例:按员工姓名的长度分组,查询每一组员工个数,筛选员工个数 > 5 的有哪些

SELECT COUNT(*),LENGTH(last_name) len_name

FROM employees

GROUP BY LENGTH(last_name)

HAVING COUNT(*) > 5;

#按多个字段分组

#案例:查询每个部门每个工种的员工的平均工资

SELECT AVG(salary),department_id,job_id FROM employees

GROUP BY department_id ,job_id;

#添加排序

##案例:查询每个部门每个工种的员工的平均工资,并且平均工资的高低显示

SELECT AVG(salary),department_id,job_id FROM employees

GROUP BY department_id ,job_id

ORDER BY AVG(salary) DESC;

进阶6 连接查询

添加测试数据库:

/*
SQLyog Ultimate v10.00 Beta1
MySQL - 5.7.18-log : Database - girls
*********************************************************************
*/
/*!40101 SET NAMES utf8 */;
/*!40101 SET SQL_MODE=''*/;
/*!40014 SET @[email protected]@UNIQUE_CHECKS, UNIQUE_CHECKS=0 */;
/*!40014 SET @[email protected]@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0 */;
/*!40101 SET @[email protected]@SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO' */;
/*!40111 SET @[email protected]@SQL_NOTES, SQL_NOTES=0 */;
CREATE DATABASE /*!32312 IF NOT EXISTS*/`girls` /*!40100 DEFAULT CHARACTER SET utf8 */;
USE `girls`;
/*Table structure for table `admin` */
DROP TABLE IF EXISTS `admin`;
CREATE TABLE `admin` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(10) NOT NULL,
`password` varchar(10) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;
/*Data for the table `admin` */
insert into `admin`(`id`,`username`,`password`) values (1,'john','8888'),(2,'lyt','6666');
/*Table structure for table `beauty` */
DROP TABLE IF EXISTS `beauty`;
CREATE TABLE `beauty` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
`sex` char(1) DEFAULT '女',
`borndate` datetime DEFAULT '1987-01-01 00:00:00',
`phone` varchar(11) NOT NULL,
`photo` blob,
`boyfriend_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=utf8;
/*Data for the table `beauty` */
insert into `beauty`(`id`,`name`,`sex`,`borndate`,`phone`,`photo`,`boyfriend_id`) values (1,'柳岩','女','1988-02-03 00:00:00','18209876577',NULL,8),(2,'苍老师','女','1987-12-30 00:00:00','18219876577',NULL,9),(3,'Angelababy','女','1989-02-03 00:00:00','18209876567',NULL,3),(4,'热巴','女','1993-02-03 00:00:00','18209876579',NULL,2),(5,'周冬雨','女','1992-02-03 00:00:00','18209179577',NULL,9),(6,'周芷若','女','1988-02-03 00:00:00','18209876577',NULL,1),(7,'岳灵珊','女','1987-12-30 00:00:00','18219876577',NULL,9),(8,'小昭','女','1989-02-03 00:00:00','18209876567',NULL,1),(9,'双儿','女','1993-02-03 00:00:00','18209876579',NULL,9),(10,'王语嫣','女','1992-02-03 00:00:00','18209179577',NULL,4),(11,'夏雪','女','1993-02-03 00:00:00','18209876579',NULL,9),(12,'赵敏','女','1992-02-03 00:00:00','18209179577',NULL,1);
/*Table structure for table `boys` */
DROP TABLE IF EXISTS `boys`;
CREATE TABLE `boys` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`boyName` varchar(20) DEFAULT NULL,
`userCP` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
/*Data for the table `boys` */
insert into `boys`(`id`,`boyName`,`userCP`) values (1,'张无忌',100),(2,'鹿晗',800),(3,'黄晓明',50),(4,'段誉',300);
/*!40101 SET [email protected]_SQL_MODE */;
/*!40014 SET [email protected]_FOREIGN_KEY_CHECKS */;
/*!40014 SET [email protected]_UNIQUE_CHECKS */;
/*!40111 SET [email protected]_SQL_NOTES */;
#连接查询
/*
含义:又称为多表查询,当查询的字段来自于多个表时,就会用到连接查询
笛卡尔积现象:表1有m行,表2 有n行,结果有m*n行
发生原因:没有有效的链接条件
如何避免:添加有效的链接条件
分类:
按年代分类(在mysql中的支持):
sql92标准 :仅仅支持内连接
sql99标准【推荐】支持内连接+外连接(左外,右外)+交叉连接
按功能分类:
内连接:
等值连接
非等值连接
自连接
外连接:
左外连接
右外连接
全外连接
交叉连接
*/
#一:sql92标准
#1、等值连接:
/*
一:多表等值连接的结果为多表的交集部分
二:m表连接,至少n-1个连接条件
三:多表的顺序没有要求
四:一般需要为表起别名
五:可以搭配前面介绍的所有子句使用,比如排序,分组,筛选
*/
#案例1:查询女生名很对应的男生名
SELECT name ,boyName FROM beauty,boys
WHERE beauty.boyfriend_id=boys.id;
USE myemployees;
#案例2:查询员工名和对应的部门名
SELECT last_name,department_name
FROM employees,departments
WHERE employees.department_id = departments.department_id;
#2、为表起别名
/*
1、提高语句的简介度
2、区分多个从重名字段
注意:如果为表起了别名,则查询的字段就不能使用原来的表名
*/
#案例:查询员工名、工种号、工种名
SELECT last_name,e.job_id,job_title
FROM employees e,jobs j
WHERE e.`job_id`=j.`job_id`;
#3、两个表的顺序是否可以调换
SELECT e.last_name,e.job_id,j.job_title
FROM jobs j,employees e
WHERE e.`job_id`=j.`job_id`;
#4、可以加筛选
#案例:查询有奖金的员工名,部门名
SELECT last_name,department_name
FROM employees e,departments d
WHERE e.department_id = d.department_id
AND e.commission_pct IS NOT NULL;
#案例2:查询城市名中第二个字符为o的部门
SELECT department_name,city
FROM departments d,locations l
WHERE d.location_id=l.location_id
AND city LIKE '_o%';
#5、可以加分组
#案例:查询每个城市的部门个数
SELECT COUNT(*) 个数,city
FROM employees d,locations l
GROUP BY city;
#案例二:查询有奖金的的每个部门名和部门领导的编号和该部门的最低工资
SELECT department_name,d.manager_id,MIN(salary) FROM departments d,employees e
WHERE d.department_id= e.department_id
AND commission_pct IS NOT NULL
GROUP BY department_name,d.manager_id;
#6、可以加排序
SELECT job_title,COUNT(*) FROM employees e,jobs j
WHERE e.job_id = j.job_id
GROUP BY job_title
ORDER BY COUNT(*) DESC;
#7、可以实现三表连接:
# 案例:查询员工名,部门名和所在城市
SELECT last_name ,department_name,city
FROM employees e,departments d,locations l
WHERE e.department_id = d.department_id
AND d.location_id = l.location_id
ORDER BY d.department_name DESC;