从绝对路径的集合还原成树形目录结构
1. 流程表格
步骤 | 描述 |
---|---|
1 | 遍历所有绝对路径 |
2 | 将每个绝对路径拆分成目录和文件名 |
3 | 根据目录结构构建树形结构 |
4 | 输出树形目录结构 |
2. 具体步骤及代码
步骤1:遍历所有绝对路径
List<String> absolutePaths = Arrays.asList("/root/folder1/file1.txt", "/root/folder2/subfolder/file2.txt");
步骤2:拆分路径
Map<String, Map<String, List<String>>> directoryStructure = new HashMap<>();
for (String path : absolutePaths) {
String[] parts = path.split("/");
String fileName = parts[parts.length - 1];
String directory = String.join("/", Arrays.copyOfRange(parts, 0, parts.length - 1));
if (!directoryStructure.containsKey(directory)) {
directoryStructure.put(directory, new HashMap<>());
}
Map<String, List<String>> directoryContents = directoryStructure.get(directory);
if (!directoryContents.containsKey("files")) {
directoryContents.put("files", new ArrayList<>());
}
directoryContents.get("files").add(fileName);
}
步骤3:构建树形结构
class Node {
String name;
Map<String, Node> children;
public Node(String name) {
this.name = name;
this.children = new HashMap<>();
}
}
Node root = new Node("");
for (String directory : directoryStructure.keySet()) {
String[] parts = directory.split("/");
Node current = root;
for (String part : parts) {
if (!current.children.containsKey(part)) {
current.children.put(part, new Node(part));
}
current = current.children.get(part);
}
current.children.putAll(directoryStructure.get(directory));
}
步骤4:输出树形结构
public void printTree(Node node, String indent) {
System.out.println(indent + node.name + "/");
for (Node child : node.children.values()) {
printTree(child, indent + " ");
}
}
printTree(root, "");
3. 类图
classDiagram
Node <|-- Main
class Node {
String name
Map<String, Node> children
Node(name)
}
class Main {
List<String> absolutePaths
Map<String, Map<String, List<String>>> directoryStructure
Node root
printTree(Node node, String indent)
}
4. 旅行图
journey
title 绝对路径集合还原成树形目录结构之旅
section 准备工作
Main 初始化数据
section 开始构建
Main 遍历绝对路径
Main 拆分路径
Main 构建树形结构
section 完成
Main 输出树形结构
通过以上步骤和代码,你可以实现将绝对路径的集合还原成树形目录结构。希望这篇文章对你有所帮助,如果有任何疑问,欢迎继续提问。祝你学习顺利!