思路:大白书上的题,经典的路径压缩并且维护权值
#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
using namespace std;
const int maxn = 20000+500;
int fa[maxn],d[maxn];
int find(int x)
{
if(x!=fa[x])
{
int root = find(fa[x]);
d[x]+=d[fa[x]];
return fa[x]=root;
}
else
return x;
}
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
int n;
scanf("%d",&n);
for(int i = 1;i<=n;i++)
{
fa[i]=i;
d[i]=0;
}
char s[2];
while(scanf("%s",s) && s[0]!='O')
{
if (s[0]=='E')
{
int u;
scanf("%d",&u);
find(u);
printf("%d\n",d[u]);
}
else
{
int u,v;
scanf("%d%d",&u,&v);
fa[u]=v;
d[u]=abs(u-v)%1000;
}
}
}
}