该脚本为,如果满足i 等于mysql、information_schema、performance_schema、db_sys_stat 其中一个那么就跳出执行下面的。

重点介绍:

if 条件语句 [ ] 左右两个都要有一个空格。
#!/bin/bash
 #2012-12-25 by cocofor i in `cat ./db_list.txt`
 doif [ "$i" == "mysql" ] || [ "$i" == "information_schema" ] || [ "$i" == "performance_schema" ] || [ "$i" == "db_sys_stat" ]; then
  continue
 else
  echo '!!!!!!!!!!!!';   done