基本异常打印:

def func(num1, num2):
    try:
        x = num1 * num2
        y = num1 / num2
        return x, y
    except Exception as e:
        print("错误信息:", e)

func(1, 0)

运行结果:

错误信息: division by zero

只能打印我们处理的结果或者将异常打印出来,不能直观的知道在哪个文件中的哪一行出错

使用Python中traceback模块来进行处理可以直观异常信息

Python解释器在打印堆栈跟踪时的行为:

import sys


def func1(num1, num2):
        x = num1 * num2
        y = num1 / num2
        return x, y
def func2():
    func1(1, 0)


if __name__ == '__main__':
    try:
        func2()
    except Exception as e:
        exc_type, exc_value, exc_traceback = sys.exc_info()
        print("exc_type:",exc_type)
        print("exc_value:",exc_value)
        print("exc_traceback:",exc_traceback)

运行结果:

exc_type: <class 'ZeroDivisionError'>
exc_value: division by zero
exc_traceback: <traceback object at 0x00000150A48461C0>

sys.exc_info()获取了当前处理的exception的相关信息,并返回一个元组
元组的第一个数据是异常的类型,第二个返回值是异常的value值,第三个是traceback object

1.traceback.print_tb

import sys
import traceback


def func1(num1, num2):
        x = num1 * num2
        y = num1 / num2
        return x, y
def func2():
    func1(1, 0)


if __name__ == '__main__':
    try:
        func2()
    except Exception as e:
        exc_type, exc_value, exc_traceback = sys.exc_info()
        traceback.print_tb(exc_traceback)

运行结果:

File "<ipython-input-3-124c9965f4c1>", line 15, in <module>
    func2()
  File "<ipython-input-3-124c9965f4c1>", line 10, in func2
    func1(1, 0)
  File "<ipython-input-3-124c9965f4c1>", line 7, in func1
    y = num1 / num2
说明:traceback.print_tb(tb, limit=None, file=None)
1.tb: 这个就是traceback object, 是我们通过sys.exc_info获取到的
2.limit: 这个是限制stack trace层级的,如果不设或者为None,就会打印所有层级的stack trace
3.file: 这个是设置打印的输出流的,可以为文件,也可以是stdout之类的file-like object。如果不设或为None,则输出到sys.stderr。

PS: 如果limit为正,则打印以limit来自traceback 对象tb的堆栈跟踪条目(从调用方的帧开始)。否则,打印最后一个abs(limit)条目。如果省略限制或无限制,则打印所有条目。如果文件被省略或无文件,则输出到sys.stderr;否则,它应该是一个打开的文件或类似文件的对象来接收输出。

2.traceback.print_exception

import sys
import traceback


def func1(num1, num2):
        x = num1 * num2
        y = num1 / num2
        return x, y
def func2():
    func1(1, 0)


if __name__ == '__main__':
    try:
        func2()
    except Exception as e:
        exc_type, exc_value, exc_traceback = sys.exc_info()
        traceback.print_exception(exc_type, exc_value, exc_traceback, limit=None, file=sys.stdout)

运行结果:

Traceback (most recent call last):
  File "<ipython-input-4-07f2fdcf0933>", line 15, in <module>
    func2()
  File "<ipython-input-4-07f2fdcf0933>", line 10, in func2
    func1(1, 0)
  File "<ipython-input-4-07f2fdcf0933>", line 7, in func1
    y = num1 / num2
ZeroDivisionError: division by zero
说明:traceback.print_exception(etype, value, tb, limit=None, file=None, chain=True)
1.前三个参数正好是sys.exc_info()返回的三个值
2.与print_tb相比,打印信息多了开头的"Traceback (most…)“信息以及最后一行的异常类型和value信息
3.还有一个不同是当异常为SyntaxError时,会有”^"来指示语法错误的位置

3.traceback.print_exc

import traceback


def func(num1, num2):
    try:
        x = num1 * num2
        y = num1 / num2
        return x, y
    except:
        traceback.print_exc(file=open('traceback.txt','w+'))

func(1, 0)

运行结果(traceback.txt):

Traceback (most recent call last):
  File "<ipython-input-7-4ce4d373a795>", line 7, in func
    y = num1 / num2
ZeroDivisionError: division by zero

或者创建内存文件对象:

import traceback
import io


def func(num1, num2):
    try:
        x = num1 * num2
        y = num1 / num2
        return x, y
    except:
        fp = io.StringIO()  # 创建内存文件对象
        traceback.print_exc(file=fp)
        message = fp.getvalue()
        print(message)
func(1, 0)

运行结果:

Traceback (most recent call last):
  File "<ipython-input-8-e2f3f41c0206>", line 8, in func
    y = num1 / num2
ZeroDivisionError: division by zero

PS:print_exc是简化版的print_exception, 由于exception type, value和traceback object都可以通过sys.exc_info()获取,因此print_exc()就自动执行exc_info()来帮助获取这三个参数。
所以traceback.print_exc(limit=None, file=None, chain=True)可将异常直接打印出来,同时可以将异常信息写入到文件中

4.traceback.format_exc

import traceback


def func(num1, num2):
    try:
        x = num1 * num2
        y = num1 / num2
        return x, y
    except:
        print(traceback.format_exc())

func(1, 0)

运行结果:

Traceback (most recent call last):
  File "<ipython-input-9-2698644ecad7>", line 7, in func
    y = num1 / num2
ZeroDivisionError: division by zero

PS:traceback.format_exc(limit=None, chain=True)返回的是一个字段串,效果与traceback.print_exc()一致,比如我们想通过logger将异常记录在log里,就可以使用format_exc