python list计算个数据结构 python计算list中某元素的个数

# 方法一
List =[1,2,2,3,3,3,4,4,4,4,5,5,5,5,5]
Strlist=['A','B','B','C','C','C','D','D','D','D']
a=set(List)
b=set(Strlist)
print(List)
print(Strlist)
print(a)
for i in a:
    count =List.count(i)
    print(i,'出现的次数：',count)
for i in b:
    count =Strlist.count(i)
    print(i,'出现的次数：',count)
print('-'*20)

#方法二
List =[1,2,2,3,3,3,4,4,4,4,5,5,5,5,5]
Strlist=['A','B','B','C','C','C','D','D','D','D']
d1 = {}
d2 = {}
for i in List:
    if List.count(i) >= 1:
        d1[i] = List.count(i)
print(d1)

for i in Strlist:
    if Strlist.count(i) >= 1:
        d2[i] = Strlist.count(i)
print(d2)

print('-'*20)

#方法三
from collections import Counter
List =[1,2,2,3,3,3,4,4,4,4,5,5,5,5,5]
Strlist=['A','B','B','C','C','C','D','D','D','D']
res = Counter(List)
print(res)
res=Counter(Strlist)
print(res)