1.快速遍历数组的每一个元素:

NSArray * array = [NSArray arrayWithObjects:@"zhangsan",@"lisi",@"wangwu",@"zhaoda",@"qianer",nil];

//方法一:快速枚举(for...in):效率最高,代码的可读性强,代码简洁易懂

for(NSString obj in array)
{
  NSLog(@"%@",obj);
}

//方法二:for循环遍历

for(int i = 0; i < [array count]; i++)
{
  NSString * obj = [array objectAtIndex:i];
  NSLog(@"%@",obj);
}

//方法三:使用枚举器NSEnumerator

NSEnumerator * enumerator = [array reverseObjectEnumerator];
NSString * obj = nil;
while(obj = [enumerator nextObject])
{
  NSLog(@"%@",obj);
}

//方法四:(block)使用专业的枚举方式

[array enumerateObjectsUsingBlock:^(id obj,NSUInteger idx,BOOL * stop){
  NSLog(@"%@---%lu",obj,idx);
  if(idx == 1){
  *stop = YES;
}
}];

2.快速遍历字典中的每一个元素

NSDictionary * dic = [NSDictionary dictionaryWithObjectsAndKeys:@"jack",@"name",@"19",@"age",@"1.8",@"height",nil];
NSArray * allkeys = [dic allkeys];
for(int i = 0; i < [dic count]; i++)
{
  NSString * key = [allkeys objectAtIndex:i];  NSString * obj = [dic objectForKey:key];
  NSLog(@"obj=%@,key=%@",obj,key);
}

3.快速遍历集合中的元素(NSSet)

NSSte * set = [NSSet  setWithObjects:@"mingren",@"zuozhu",@"haizei",@"xiaoxin",nil];
NSString * obj = [set allObjects];
for(int i = 0; i < [set count]; i++)
{  
  NSLog(@"%@",[obj objectAtIndex:i]);
}

以上就是有关数组,字典和集合的遍历元素的方法,方法还有很多,希望和各位同学相互学习,相互成长!