mysql查找每个班级分数最高的的学生 mysql查询最高分学生的学号

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mob6454cc696f04 2024-06-09 07:37:59

文章标签 mysql查找每个班级分数最高的的学生软件测试自动化测试 MySQL ci 文章分类 MySQL 数据库

-- students表 SID, Sname, sage,ssex
-- teacher表  TID,Tname
-- course表  CID,Cname,TID
-- sc表  SID,CID,Score
-- 1.查询课程C01比C02课程成绩高的所有学生的学号
select sc1.SID from
(select SID,CID,Score from sc where CID='C01') as sc1
join
(select SID,CID,Score from sc where CID='C02') as sc2
on sc1.SID=SC2.SID where sc1.Score>sc2.SCore;

insert into sc values('S003','C03','100');
-- 2.查询平均成绩大于60分的学号和姓名alter
select a.SID,students.Sname,a.avg_score from
(select SID,avg(Score) as avg_score from sc group by sid having avg(score)>=60) as a
join
students
on a.SID=students.SID;

-- 3.查询所有同学的学号、姓名、选课数、总成绩
select stud.SID,stud.Sname,a.count_cid,a.sum_sc from
(select SID,Sname from students) as stud
left join
(select SID,count(CID) as count_cid,sum(score) as sum_sc from sc group by SID) AS a
on stud.SID=a.SID;

-- 4 查询姓“李”的老师的个数，不能重复
select count(distinct(TID)) from teacher where TName like "李%";

-- 5 查询没有学过张三老师课的学号和姓名
select SID from sc where CID not in(
select a.CID from
(select CID,TID from course) as a
join
(select TID from teacher where Tname='张三') as b
on a.TID=b.TID);

-- 6 查询两门以上不及格课程的同学的学号及其平均成绩
select SID, avg(score) from sc where SID in
(select SID from sc where score<60 group by SID having count(cid)>=2);


select count(distinct(SID)) as stu_num from students;
select count(distinct(sid)) from sc group by CID;
-- 7全部学生都选修的课程
select CID from sc group by CID having count(distinct(SID))= 
(select count(distinct(SID)) as stu_num from students);

-- 8统计每门学生的选修人数，超过2名的才统计
select CID,count(distinct(SID)) from sc group by CID having count(distinct(SID))>=2;

-- 9查询每门功课最好的前两名，输出学号和课程ID,成绩，按课程号升序排列，成绩按降序排列
select SID,CID,score from sc AS A where SID in 
(select SID from (select SID from sc where CID=A.CID order by score desc limit 0,2) as a)
order by CID,score desc;

-- 10 查询选修张三老师课程的学生中，成绩最高的学生姓名以及成绩
select b.SID,b.sname,a.CID,max(a.score) from
(select SID,Sname from students) as b
join
(select CID,SID,score from sc where CID in
(select CID from course where TID=
(select TID from teacher where TName="张三"))) as a 
on b.SID=a.SID;

-- 11 查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程号升序排列alter
select CID,avg(score) from sc group by CID order by avg(score) desc,CID ASC;

-- 12 查询学生总成绩以及名次

-- 13统计各科成绩·，各分段人数，结果包括课程ID、课程名称，[100-85],[85-70],[70-60],[ <60]
    select sc.CID,a.Cname,SUM(CASE WHEN Score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS "[100 - 85]",
        SUM(CASE WHEN Score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS "[85 - 70]",
        SUM(CASE WHEN Score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS "[70 - 60]",
        SUM(CASE WHEN Score < 60 THEN 1 ELSE 0 END) AS "[60 -]"
    from
    (select Cname,CID from  course) as a
    join
    sc
    on a.CID=sc.CID group by sc.CID;
    
    -- 14 查询各科的及格率
    -- C02没有查询到，因为C02满足socre>60的记录为0
    select CID,count(distinct(SID)) as num from sc where score>60 group by CID;
    select a.CID,a.num,b.sum_num from
    (select CID,count(distinct(SID)) as num from sc where score>60 group by CID) as a
    left join
    (select CID,count(distinct(SID)) as sum_num from sc group by CID) as b
    on a.CID=B.CID;
    
    -- 正解
    select b.CID,a.num/b.sum_num from
    (select CID,count(SID) as sum_num from sc group by CID) as b
    join
    (select CID,sum(case when score>=60 then 1 else 0 end) as num from sc group by CID)as a
    on b.CID=a.CID;
    
    -- 15 求各科的最低分和最高分
    select CID,max(score),min(score) from sc group by CID;
    
    -- 16 查询出生2000年之前的学生名单
    select SID,Sname from students where extract(year from now())-sage<=2000;
    -- 17 查询选课少于两门课程的学生名单
    select SID,Sname from students where SID not in(select SID from sc group by SID having count(CID)>=2);

    -- 18 查询英语成绩第三名的学生成绩单 
    select * from sc where SID=(select SID from sc where CID=
    (select CID from course where Cname="英语") order by score limit 2,1);

mysql时间函数

1.curtime() 返回当前时间 eg. 23:26:30

2.curdate() 返回当前日期 eg. 2020-6-11

3.now() 返回当前日期时间 eg.2020-6-11 23:26:30

4.date() 提取日期部分 eg.date(now()) 2020-6-11

5.datediff() 返回两个日期之前的天数 eg.datediff(‘2020-6-11’,‘2020-5-11’) 输出30

6.extract(unit from date) 提取日期时间的单独部分

unit值

Unit 值
MICROSECOND
SECOND
MINUTE
HOUR
DAY
WEEK
MONTH
QUARTER
YEAR
SECOND_MICROSECOND
MINUTE_MICROSECOND
MINUTE_SECOND
HOUR_MICROSECOND
HOUR_SECOND
HOUR_MINUTE
DAY_MICROSECOND
DAY_SECOND
DAY_MINUTE
DAY_HOUR
YEAR_MONTH