问题

​https://leetcode-cn.com/problems/reverse-integer/​

练习使用JavaScript解答

/**
* @param {number} x
* @return {number}
*/
var reverse = function(x) {
var flag = (x < 0) ? true : false;
x = (x < 0) ? -x : x;
var a = 0;
while(x > 0) {
a = a * 10 + x % 10;
x = Math.floor(x/10);
}
a = flag ? -a : a;
if(a <= Math.pow(-2,31) || a > Math.pow(2,31)-1)
return 0;
return a;
};