帖一个歪果仁的解决方案,测试没有问题。建议使用此方式。


Here is the code that works for me. The key is that you need a wrapper class.

public class Person {

private String name;
private Integer age;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public Integer getAge() {
return age;
}

public void setAge(Integer age) {
this.age = age;
}

@Override
public String toString() {
return "Person [name=" + name + ", age=" + age + "]";
}

A PersonWrapper class

public class PersonWrapper {

private List<Person> persons;

/**
* @return the persons
*/
public List<Person> getPersons() {
return persons;
}

/**
* @param persons the persons to set
*/
public void setPersons(List<Person> persons) {
this.persons = persons;
}
}

My Controller methods

@RequestMapping(value="person", method=RequestMethod.POST,consumes="application/json",produces="application/json")
@ResponseBody
public List<String> savePerson(@RequestBody PersonWrapper wrapper) {
List<String> response = new ArrayList<String>();
for (Person person: wrapper.getPersons()){
personService.save(person);
response.add("Saved person: " + person.toString());
}
return response;
}

The request sent is json in POST

{"persons":[{"name":"shail1","age":"2"},{"name":"shail2","age":"3"}]}

And the response is

["Saved person: Person [name=shail1, age=2]","Saved person: Person [name=shail2, age=3]"]

​ http://stackoverflow.com/questions/23012841/receiving-json-and-deserializing-as-list-of-object-at-spring-mvc-controller ​