You are given a number k and a string s of length n, consisting of the characters ‘.’ and ‘’. You want to replace some of the '’ characters with ‘x’ characters so that the following conditions are met:

The first character ‘’ in the original string should be replaced with ‘x’;
The last character '
’ in the original string should be replaced with ‘x’;
The distance between two neighboring replaced characters ‘x’ must not exceed k (more formally, if you replaced characters at positions i and j (i<j) and at positions [i+1,j−1] there is no “x” symbol, then j−i must be no more than k).
For example, if n=7, s=..* and k=3, then the following strings will satisfy the conditions above:

.xx.xx;
.x
.xx;
.xx.xxx.
But, for example, the following strings will not meet the conditions:
.**.xx (the first character '’ should be replaced with ‘x’);
.x
.xx* (the last character ‘’ should be replaced with ‘x’);
.x
.xx (the distance between characters at positions 2 and 6 is greater than k=3).
Given n, k, and s, find the minimum number of '
’ characters that must be replaced with ‘x’ in order to meet the above conditions.

Input

The first line contains one integer t (1≤t≤500). Then t test cases follow.

The first line of each test case contains two integers n and k (1≤k≤n≤50).

The second line of each test case contains a string s of length n, consisting of the characters ‘.’ and ‘*’.

It is guaranteed that there is at least one ‘*’ in the string s.

It is guaranteed that the distance between any two neighboring ‘*’ characters does not exceed k.

Output

For each test case output the minimum number of ‘*’ characters that must be replaced with ‘x’ characters in order to satisfy the conditions above.

#include<bits/stdc++.h>
using namespace std;
#define ll long long
char a[100010];

int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n,k;
scanf("%d%d",&n,&k);
scanf("%s",a);
int cut = 0;
for(int i=0;i<n;i++)
{
if(a[i]=='*')
cut++;
}

if(cut==0||cut==1)
{
printf("%d\n",cut == 0?0:1);
continue;
}

int head = 0;
for(int i = 0; i < n; i++)
{
if(a[i] == '*')
{
a[i] = 'x';
head = i;
break;
}
}
for(int i = n; i >= 0; i--)
{
if(a[i] == '*')
{
a[i] = 'x';
break;
}
}
// for(int i = head; i < n; i++)
// {
// if(a[i] == '*')
// {
// head = i;
// break;
// }
// }
int ans = 0,b = head,f = 0;
for(int i=head; i < n; i++)
{
for(int j=i+1;j<=i+k;j++)
{
if(a[j]=='*')
b=j;
else if(a[j]=='x')
{
cout<<ans+2<<endl;
f=1;
break;
}
}
if(f==1)
break;
i=b-1;
ans++;
}
}
}