1153 Decode Registration Card of PAT (25 point(s))
A registration card number of PAT consists of 4 parts:
- the 1st letter represents the test level, namely,
T
for the top level,A
for advance andB
for basic; - the 2nd - 4th digits are the test site number, ranged from 101 to 999;
- the 5th - 10th digits give the test date, in the form of
yymmdd
; - finally the 11th - 13th digits are the testee's number, ranged from 000 to 999.
Now given a set of registration card numbers and the scores of the card owners, you are supposed to output the various statistics according to the given queries.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N (≤104) and M (≤100), the numbers of cards and the queries, respectively.
Then N lines follow, each gives a card number and the owner's score (integer in [0,100]), separated by a space.
After the info of testees, there are M lines, each gives a query in the format Type Term
, where
-
Type
being 1 means to output all the testees on a given level, in non-increasing order of their scores. The correspondingTerm
will be the letter which specifies the level; -
Type
being 2 means to output the total number of testees together with their total scores in a given site. The correspondingTerm
will then be the site number; -
Type
being 3 means to output the total number of testees of every site for a given test date. The correspondingTerm
will then be the date, given in the same format as in the registration card.
Output Specification:
For each query, first print in a line Case #: input
, where #
is the index of the query case, starting from 1; and input
is a copy of the corresponding input query. Then output as requested:
- for a type 1 query, the output format is the same as in input, that is,
CardNumber Score
. If there is a tie of the scores, output in increasing alphabetical order of their card numbers (uniqueness of the card numbers is guaranteed); - for a type 2 query, output in the format
Nt Ns
whereNt
is the total number of testees andNs
is their total score; - for a type 3 query, output in the format
Site Nt
whereSite
is the site number andNt
is the total number of testees atSite
. The output must be in non-increasing order ofNt
's, or in increasing order of site numbers if there is a tie ofNt
.
If the result of a query is empty, simply print NA
.
Sample Input:
Sample Output:
经验总结:
emmmm 第一遍直接AC,这一次就。。。一个段错误,一个超内存,很尴尬- -|||所以考试能不能AC,还是看状态的= =,这一题,实际上难的点,就在第三种类型的存储上面,可以肯定要用映射(map或者unordered_map),至于map的类型是什么,这就是一个问题,map<string,map<int,int> >就可以了,因为只要存储考场号以及人数,但是,这种情况没法在查询前进行排序,当然,也没必要进行,在查询时,针对查询的考场,建立一个vector<pair<int,int> > 收集其中的考场号和人数,然后再进行排序,最后输出就行啦~
AC代码