按d排序保证最大惩罚最小,但是此时次大惩罚+最大惩罚不一定最小,可以牺牲一个任务使得最大惩罚增大,次大惩罚减小使得最终答案减小

#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000;
int T, N, ans;
struct Data {
int s, d, x;
bool operator < (const Data& rhs) const {
if (d != rhs.d) return d < rhs.d;
return s < rhs.s;
}
}node[maxn], temp[maxn];
void solve() {
int t = 0, maxv = 0, maxv_ = 0;
for (int i = 1; i <= N; i++) {
t += temp[i].s;
if (t - temp[i].d > maxv_) {
maxv_ = t - temp[i].d;
}
if (maxv_ > maxv) swap(maxv_, maxv);
}
ans = min(ans, maxv + maxv_);
}
int main() {
scanf("%d", &T);
while (T--) {
scanf("%d", &N);
for (int i = 1; i <= N; i++) scanf("%d %d", &node[i].s, &node[i].d);
sort(node+1, node+N+1);
int t = 0, maxv = 0, maxv_ = 0, pos;
for (int i = 1; i <= N; i++) {
t += node[i].s;
if (t - node[i].d >= maxv_) {
pos = i;
maxv_ = t - node[i].d;
}
if (maxv_ > maxv) swap(maxv_, maxv);
}
ans = maxv + maxv_;
for (int i = pos+1; i <= N; i++) temp[i] = node[i];
for (int i = 1; i < pos; i++) {
for (int j = 1; j < i; j++) temp[j] = node[j];
for (int j = i; j < pos; j++) temp[j] = node[j+1];
temp[pos] = node[i];
solve();
}
printf("%d\n", ans);
}
return 0;
}