测试获得url的地址

1.编写一个TestGetUrl的测试类，代码如下：

package eduask;
 import java.io.IOException;
 import javax.servlet.ServletException;
 import javax.servlet.http.HttpServlet;
 import javax.servlet.http.HttpServletRequest;
 import javax.servlet.http.HttpServletResponse;
 //测试获得url的地址;
 public class TestGetUrl extends HttpServlet {
 @Override
 protected void service(HttpServletRequest req, HttpServletResponse resp)
 throws ServletException, IOException {
 String url=req.getRequestURI();
 System.out.println(url);
 resp.getWriter().write(url);
 }
 }

2.在web.xml文件中配置相关属性，配置结果如下为：

<!--测试获得url-->
 <servlet>
 <servlet-name>url</servlet-name>
 <servlet-class>eduask.TestGetUrl</servlet-class>
 </servlet>
 <servlet-mapping>
 <servlet-name>url</servlet-name>
 <url-pattern>/url</url-pattern>
 </servlet-mapping>

3.启动tomcat，之后在浏览器中输入​​http://localhost:8080/webDemo/url​​

4.浏览器中会显示：/webDemo/url

5.控制台会显示：/webDemo/url