解决报错TypeError：unsupported operand type(s) for +: ‘NoneType‘ and ‘str‘

文章目录

一、问题描述

from pyspark.sql.types import StringType

@udf(returnType = StringType())
def bad_funify(s):
    return s + " is fun!"

countries2 = spark.createDataFrame([("Thailand", 3), (None, 4)], ["country", "id"])
countries2.withColumn("fun_country", bad_funify("country")).show()

用一个udf想让df（有country和id两个字段）生成新的一列​​fun_country​​​（内容是字符串，内容为​​country xx is fun​​​），但是df中有的​​country​​​字段内容没有数据（注意类型是​​None​​​而不是​​null​​），结果报错如下：

PythonException: 
  An exception was thrown from the Python worker. Please see the stack trace below.
Traceback (most recent call last):
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/worker.py", line 619, in main
    process()
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/worker.py", line 611, in process
    serializer.dump_stream(out_iter, outfile)
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/serializers.py", line 211, in dump_stream
    self.serializer.dump_stream(self._batched(iterator), stream)
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/serializers.py", line 132, in dump_stream
    for obj in iterator:
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/serializers.py", line 200, in _batched
    for item in iterator:
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/worker.py", line 452, in mapper
    result = tuple(f(*[a[o] for o in arg_offsets]) for (arg_offsets, f) in udfs)
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/worker.py", line 452, in <genexpr>
    result = tuple(f(*[a[o] for o in arg_offsets]) for (arg_offsets, f) in udfs)
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/worker.py", line 87, in <lambda>
    return lambda *a: f(*a)
  File "/usr/lib/spark-current/python/lib/pyspark.zip/pyspark/util.py", line 74, in wrapper
    return f(*args, **kwargs)
  File "<ipython-input-1051-5a6c51e7c332>", line 5, in bad_funify
TypeError: unsupported operand type(s) for +: 'NoneType' and 'str'

二、解决方案

这是个很蠢的问题。其实如果​​country​​​为空值时，​​fun_country​​​应该也是空的，所以就简单加多个判断的逻辑即可。修改udf为​​good_funity​​后：

@udf(returnType=StringType())
def good_funify(s):
     return None if s == None else s + " is fun!"
countries2.withColumn("fun_country", good_funify("country")).show()

+--------+---+----------------+
| country| id|     fun_country|
+--------+---+----------------+
|Thailand|  3|Thailand is fun!|
|    null|  4|            null|
+--------+---+----------------+

Reference

[1] ​​Navigating None and null in PySpark​​