Restoring the Permutation


from Codeforces Round #710 (Div. 3)
Time limit:2s
Memory limit:256MB

Restoring the Permutation | Codeforces_stl


Restoring the Permutation | Codeforces_算法_02


这个题目,题目读懂了就很简单,stl应用,我学到了

对于每一个测试,相同的数,第一个原型输出,后面的在比它小的数里面依次找最小的,第二个输出依次找最大的。

ac代码:
#include<iostream>
#include<set>
using namespace std;
int t,n;
int x[200005];
void solve(){
set<int> s;
for(int i = 1;i <= n;++i)
s.insert(i);
for(int i = 1;i <= n;++i)
if(x[i] != x[i - 1])
cout<<x[i]<<" ",s.erase(x[i]);
else
cout<<*s.begin()<<" ",s.erase(s.begin());
cout<<"\n";
for(int i = 1;i <= n;++i)
s.insert(i);
for(int i = 1;i <= n;++i)
if(x[i] != x[i - 1])
cout<<x[i]<<" ",s.erase(x[i]);
else
cout<<*prev(s.lower_bound(x[i]))<<" ",s.erase(*prev(s.lower_bound(x[i])));
cout<<"\n";
}
int main(){
cin>>t;
while(t--){
cin>>n;
for(int i = 1;i <= n;++i)
cin>>x[i];
solve();
}
return 0;
}