【Leetcode_easy】690. Employee Importance

problem

​​690. Employee Importance​​

题意：所有下属和自己的重要度之和，所有下属包括下属的下属即直接下属和间接下属。

solution:DFS;

/*
// Employee info
class Employee {
public:
    // It's the unique ID of each node.
    // unique id of this employee
    int id;
    // the importance value of this employee
    int importance;
    // the id of direct subordinates
    vector<int> subordinates;
};
*/
class Solution {
public:
    int getImportance(vector<Employee*> employees, int id) {
        unordered_map<int, Employee*> mymap;//err.
        for(auto employee:employees) mymap[employee->id] = employee;
        return helper(id, mymap);
    }
    int helper(int id, unordered_map<int, Employee*> m) {
        int res = m[id]->importance;
        for(auto num:m[id]->subordinates)//err.
        {
            res += helper(num, m);
        }
        return res;
    }
};

 solution:BFS;

 

 

 

参考

1. ​​Leetcode_easy_690. Employee Importance​​;

2. ​​Grandyang​​;

完