Problem Description
There are 2 special dices on the table. On each face of the dice, a distinct number was written. Consider a1.a2,a3,a4,a5,a6 to be numbers written on top face, bottom face, left face, right face, front face and back face of dice A. Similarly, consider b1.b2,b3,b4,b5,b6 to be numbers on specific faces of dice B. It’s guaranteed that all numbers written on dices are integers no smaller than 1 and no more than 6 while ai ≠ aj and bi ≠ bj for all i ≠ j. Specially, sum of numbers on opposite faces may not be 7.
At the beginning, the two dices may face different(which means there exist some i, ai ≠ bi). Ddy wants to make the two dices look the same from all directions(which means for all i, ai = bi) only by the following four rotation operations.(Please read the picture for more information)
Now Ddy wants to calculate the minimal steps that he has to take to achieve his goal.
Input
There are multiple test cases. Please process till EOF.
For each case, the first line consists of six integers a1,a2,a3,a4,a5,a6, representing the numbers on dice A.
The second line consists of six integers b1,b2,b3,b4,b5,b6, representing the numbers on dice B.
Output
For each test case, print a line with a number representing the answer. If there’s no way to make two dices exactly the same, output -1.
Sample Input
1 2 3 4 5 6
1 2 3 4 5 6
1 2 3 4 5 6
1 2 5 6 4 3
1 2 3 4 5 6
1 4 2 5 3 6
Sample Output
0
3
-1
Source
2014 ACM/ICPC Asia Regional Xi’an Online
暴力bfs 即可；
这里我们用set 进行判重；
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<bitset>
#include<ctime>
#include<deque>
#include<stack>
#include<functional>
#include<sstream>
#include<cctype>
//#pragma GCC optimize("O3")
using namespace std;
#define maxn 200005
#define inf 0x3f3f3f3f
#define INF 0x7fffffff
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const int mod = 1e9 + 7;
#define Mod 20100403
#define sq(x) (x)*(x)
#define eps 1e-10
const int N = 1505;
inline int rd() {
int x = 0;
char c = getchar();
bool f = false;
while (!isdigit(c)) {
if (c == '-') f = true;
c = getchar();
}
while (isdigit(c)) {
x = (x << 1) + (x << 3) + (c ^ 48);
c = getchar();
}
return f ? -x : x;
}
ll gcd(ll a, ll b) {
return b == 0 ? a : gcd(b, a%b);
}
ll sqr(ll x) { return x * x; }
struct node {
string s;
int stp;
};
queue<node>q;
node tmp, tmps;
int num[10];
string a, b;
set<string>st;
int main()
{
//ios::sync_with_stdio(false);
while (rdint(num[0]) != EOF) {
// a = ""; b = "";
a = "123456"; b = "123456";
for (int i = 1; i < 6; i++)rdint(num[i]);
for (int i = 0; i < 6; i++) {
a[i] = (char)(num[i] + '0');
rdint(num[i]);
b[i] = (char)(num[i] + '0');
}
int i, j;
int fg1=0, fg2;
// cout << a << ' ' << b << endl;
for ( i = 0; i < 6; i+=2) {
for ( j = 0; j < 6; j += 2) {
if (a[i] == b[j] && a[i + 1] == b[j + 1] || a[i] == b[j + 1] && a[i + 1] == b[j])
break;
}
if (j >= 6)fg1++;
}
if (fg1 == 3) {
cout << -1 << endl;
}
else {
fg2 = -1;
tmp.s = a; tmp.stp = 0;
// tmps.s = a; tmps.stp = 0;
int curans = 0;
q.push(tmp);
while (!q.empty()) {
tmp = q.front(); q.pop();
if (tmp.s == b) {
fg2 = tmp.stp;
break;
}
a = tmp.s; curans = tmp.stp;
// left
tmp.s[4] = a[4]; tmp.s[5] = a[5];
tmp.s[0] = a[3]; tmp.s[1] = a[2];
tmp.s[2] = a[0]; tmp.s[3] = a[1];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// right
tmp.s[4] = a[4]; tmp.s[5] = a[5];
tmp.s[0] = a[2]; tmp.s[1] = a[3];
tmp.s[2] = a[1]; tmp.s[3] = a[0];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// front
tmp.s[2] = a[2]; tmp.s[3] = a[3];
tmp.s[0] = a[5]; tmp.s[1] = a[4];
tmp.s[4] = a[0]; tmp.s[5] = a[1];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// back
tmp.s[2] = a[2]; tmp.s[3] = a[3];
tmp.s[0] = a[4]; tmp.s[1] = a[5];
tmp.s[4] = a[1]; tmp.s[5] = a[0];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
}
if (fg2 != -1) {
cout << fg2 << endl;
}
else cout << -1 << endl;
while (!q.empty())q.pop();
st.clear();
}
}
}
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<bitset>
#include<ctime>
#include<deque>
#include<stack>
#include<functional>
#include<sstream>
#include<cctype>
//#pragma GCC optimize("O3")
using namespace std;
#define maxn 200005
#define inf 0x3f3f3f3f
#define INF 0x7fffffff
#define rdint(x) scanf("%d",&x)
#define rdllt(x) scanf("%lld",&x)
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int U;
#define ms(x) memset((x),0,sizeof(x))
const int mod = 1e9 + 7;
#define Mod 20100403
#define sq(x) (x)*(x)
#define eps 1e-10
const int N = 1505;
inline int rd() {
int x = 0;
char c = getchar();
bool f = false;
while (!isdigit(c)) {
if (c == '-') f = true;
c = getchar();
}
while (isdigit(c)) {
x = (x << 1) + (x << 3) + (c ^ 48);
c = getchar();
}
return f ? -x : x;
}
ll gcd(ll a, ll b) {
return b == 0 ? a : gcd(b, a%b);
}
ll sqr(ll x) { return x * x; }
struct node {
string s;
int stp;
};
queue<node>q;
node tmp, tmps;
int num[10];
string a, b;
set<string>st;
int main()
{
//ios::sync_with_stdio(false);
while (rdint(num[0]) != EOF) {
// a = ""; b = "";
a = "123456"; b = "123456";
for (int i = 1; i < 6; i++)rdint(num[i]);
for (int i = 0; i < 6; i++) {
a[i] = (char)(num[i] + '0');
rdint(num[i]);
b[i] = (char)(num[i] + '0');
}
int i, j;
int fg1=0, fg2;
// cout << a << ' ' << b << endl;
for ( i = 0; i < 6; i+=2) {
for ( j = 0; j < 6; j += 2) {
if (a[i] == b[j] && a[i + 1] == b[j + 1] || a[i] == b[j + 1] && a[i + 1] == b[j])
break;
}
if (j >= 6)fg1++;
}
if (fg1 == 3) {
cout << -1 << endl;
}
else {
fg2 = -1;
tmp.s = a; tmp.stp = 0;
// tmps.s = a; tmps.stp = 0;
int curans = 0;
q.push(tmp);
while (!q.empty()) {
tmp = q.front(); q.pop();
if (tmp.s == b) {
fg2 = tmp.stp;
break;
}
a = tmp.s; curans = tmp.stp;
// left
tmp.s[4] = a[4]; tmp.s[5] = a[5];
tmp.s[0] = a[3]; tmp.s[1] = a[2];
tmp.s[2] = a[0]; tmp.s[3] = a[1];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// right
tmp.s[4] = a[4]; tmp.s[5] = a[5];
tmp.s[0] = a[2]; tmp.s[1] = a[3];
tmp.s[2] = a[1]; tmp.s[3] = a[0];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// front
tmp.s[2] = a[2]; tmp.s[3] = a[3];
tmp.s[0] = a[5]; tmp.s[1] = a[4];
tmp.s[4] = a[0]; tmp.s[5] = a[1];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
// back
tmp.s[2] = a[2]; tmp.s[3] = a[3];
tmp.s[0] = a[4]; tmp.s[1] = a[5];
tmp.s[4] = a[1]; tmp.s[5] = a[0];
tmp.stp = curans + 1;
if (st.find(tmp.s) == st.end()) {
st.insert(tmp.s); q.push(tmp);
}
}
if (fg2 != -1) {
cout << fg2 << endl;
}
else cout << -1 << endl;
while (!q.empty())q.pop();
st.clear();
}
}
}
