方案一:不定顺序:要除以6.
方案二:人为规定:a <= b <= c
方案一
package com.atguigu.TEST;
class Main{
public static void main(String[] args) {
int sum=0;
for (int i = 1; i <=1999; i++) {
for (int j = 1; j <=1999; j++) {
for (int k = 1; k <=1999; k++) {
if((i+j+k==2019)&&check(i)&&check(j)&&check(k)&&(i!=j)&&(j!=k)&&(i!=k))
{
sum++;
}
}
}
}
System.out.println(sum/6);
}
public static boolean check(int i){
String a=i+"";
if (a.indexOf('2')!=-1){
return false;
}
if (a.indexOf('4')!=-1){
return false;
}
return true;
}
}
方案二
package com.atguigu.TEST;
class Main{
public static void main(String[] args) {
int sum=0;
for (int i = 1; i <=1999; i++) {
for (int j = i+1; j <=1999; j++) {
for (int k = j+1; k <=1999; k++) {
if((i+j+k==2019)&&check(i)&&check(j)&&check(k)&&(i!=j)&&(j!=k))
{
sum++;
}
}
}
}
System.out.println(sum);
}
public static boolean check(int i){
String a=i+"";
if (a.indexOf('2')!=-1){
return false;
}
if (a.indexOf('4')!=-1){
return false;
}
return true;
}
}
答案
40785