Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/single-number
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class Solution {
public int singleNumber(int[] nums) {
for(int i=1;i<nums.length;i++)
nums[i] ^= nums[i-1];
return nums[nums.length-1];
}
}
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