#!/bin/bash
platform=$1
if[ "$platform" = "ibmaix64" ]
then
echo "$platform"
else
echo "hello ooo"
fi
Error ： syntax error near unexpected token `then'
原因： 条件语句 [ 符号的两边都要留空格
if [ $platform = "winx64" ]-----------------------right 绿色标记为空格
if[ $platform = "winx64" ]-----------------------wrong
if [$platform = "winx64" ]-----------------------wrong
2. 总结
2.1 空格
a.定义变量时, =号的两边不可以留空格
b.if语句 [ 符号的两边都要留空格
c.字符串比较, =两边要留空格
d. if 和then 在同一行 要加；
2.2 if 语句
#!/bin/sh
a=10
b=20
if [ $a == $b ]
then
echo "a is equal to b"
fi
#!/bin/sh
a=10
b=20
if [ $a == $b ]
then
echo "a is equal to b"
else
echo "a is not equal to b"
fi
#!/bin/sh
a=10
b=20
if [ $a == $b ]
then
echo "a is equal to b"
elif [ $a -gt $b ]
then
echo "a is greater than b"
elif [ $a -lt $b ]
then
echo "a is less than b"
else
echo "None of the condition met"
fi
