SQLite两个时间日期相差天数julianday的计算(26)_Time

selECT   
  julianday( datetime('2015-01-05 00:00:00') )-  
  julianday(  strftime('%Y-%m-%d %H:%M:%S',recordDate )   )
from weather

SQLite两个时间日期相差天数julianday的计算(26)_Time_02

julianday（）函数精确到秒，所以要 添加Time小时和秒

 

DATEDIFF(w1.recordDate, w2.recordDate) = 1;

 

写法为

julianday(  strftime('%Y-%m-%d %H:%M:%S',  w1.recordDate ))-  
  julianday(  strftime('%Y-%m-%d %H:%M:%S',  w2.recordDate ))=1

 相差多少个月

SELECT (strftime('%Y', '2024-05-01', 'localtime') - strftime('%Y', recordDate, 'localtime')) * 12 +
       (strftime('%m', '2024-05-01', 'localtime') - strftime('%m', recordDate, 'localtime'))

相差多少年

SELECT (strftime('%Y', '2024-05-01', 'localtime') - strftime('%Y', recordDate, 'localtime'))