运行

运行时配置解密秘钥

-Djasypt.encryptor.password=

在idea中运行

jasypt-spring-boot_spring

jasypt-spring-boot_java_02

 

命令行启动和docker中运行参见

Spring Boot: How to encrypt properties in application.properties

 

Sometimes you don’t want your properties to stay as plain text in application.properties file. Maybe you are connecting to a database and you have to write your database password in application.properties. In this tutorial, I am going to use Jasypt library for that purpose. Jasypt (Java Simplified Encryption) is a java library which allows the developer to add basic encryption capabilities to his/her projects with minimum effort, and without the need of having deep knowledge on how cryptography works.

Let’s begin,
First, add the related dependency to the project. I am using maven, so I will add the maven dependency to my pom.xml

<!-- https://mvnrepository.com/artifact/com.github.ulisesbocchio/jasypt-spring-boot-starter -->

<dependency>
<groupId>com.github.ulisesbocchio</groupId>
<artifactId>jasypt-spring-boot-starter</artifactId>
<version>2.0.0</version>
</dependency>

In the application.properties (or yaml), we will write our encrypted properties between parenthesis and put ENC keyword before it. Like;

MyProperty=ENC(23ClLWiedLx8v6XT6Wk+Bg==)

 

How to generate those encrpyted values? We will use Jasypt for that! Go to ​​http://www.jasypt.org/​​ and download the latest version. When you are done, go into jasypt\bin and use the encrypt.sh or encrypt.bat to encrypt your variables. There are several algorithms to pick but I will leave it as default and only give my property value and secret to encrpyt it.

jasypt-spring-boot_github_03

We only need to add @EnableConfigurationProperties annotation to our application and jasypt will automaticly detect encrypted values and decrypt them before they are being used. The CommandLineRunner I have added below is just to test the decryption mechanism.

@EnableEncryptableProperties
@SpringBootApplication
public class JasyptExampleApplication {

public static void main(​​​String​​​[] args) {
SpringApplication.run(JasyptExampleApplication.class, args);
}

@​​​Component​​​ public class MyRunner implements CommandLineRunner {

@Value("${myProperty}")
private ​​String​​ myProperty;

@Override
public void run(​​String​​... args) throws ​​Exception​​ {
​​System​​.out.println("My property is = " + myProperty);
}

}
}

 

But if you run your code like this, you will get the below error:

 

Error creating bean with name 'demo.JasyptExampleApplication$MyRunner': Injection of autowired dependencies failed; nested exception is java.lang.IllegalStateException: Required Encryption configuration property missing: jasypt.encryptor.password

This is because Jasypt needs to know the secret(password) to decrypt the property. We can tell this to our program several ways:
1- We can give it as a command line argument when running the application;
–jasypt.encryptor.password=MY_SECRET
2- We can set it as an environment variable, this is also useful when you are running your application on Tomcat. You can give it to Tomcat’s setenv.sh file;
export CATALINA_OPTS=”-Djasypt.encryptor.password=MY_SECRET”
You can also unset the environment variable after running the application, so there will be no doorway left behind, at least in a human-readable sense.
3- You can give it in application.properties but this might be the dumbest way as it has no difference with giving the property as plain text.
If you know a better way, write a comment below!

Now let’s look at the final output:

2018-04-25 14:03:26.413 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource configurationProperties [org.springframework.boot.context.properties.source.ConfigurationPropertySourcesPropertySource] to AOP ​​Proxy​​​2018-04-25 14:03:26.413 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource commandLineArgs [org.springframework.core.env.SimpleCommandLinePropertySource] to EncryptableEnumerablePropertySourceWrapper
2018-04-25 14:03:26.414 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource systemProperties [org.springframework.core.env.MapPropertySource] to EncryptableMapPropertySourceWrapper
2018-04-25 14:03:26.414 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource systemEnvironment [org.springframework.boot.env.SystemEnvironmentPropertySourceEnvironmentPostProcessor$OriginAwareSystemEnvironmentPropertySource] to EncryptableMapPropertySourceWrapper
2018-04-25 14:03:26.414 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource random [org.springframework.boot.env.RandomValuePropertySource] to EncryptablePropertySourceWrapper
2018-04-25 14:03:26.415 INFO 10028 --- [ main] c.u.j.EncryptablePropertySourceConverter : Converting PropertySource applicationConfig: [classpath:/application.properties] [org.springframework.boot.env.OriginTrackedMapPropertySource] to EncryptableMapPropertySourceWrapper
2018-04-25 14:03:26.468 INFO 10028 --- [ main] c.u.j.r.DefaultLazyPropertyResolver : Property ​​Resolver​​ custom Bean not found with name 'encryptablePropertyResolver'. Initializing Default Property ​​Resolver​​2018-04-25 14:03:26.470 INFO 10028 --- [ main] c.u.j.d.DefaultLazyPropertyDetector : Property Detector custom Bean not found with name 'encryptablePropertyDetector'. Initializing Default Property Detector
2018-04-25 14:03:26.472 INFO 10028 --- [ main] c.u.j.encryptor.DefaultLazyEncryptor : ​​String​​ Encryptor custom Bean not found with name 'jasyptStringEncryptor'. Initializing Default ​​String​​ Encryptor
2018-04-25 14:03:26.478 INFO 10028 --- [ main] c.u.j.encryptor.DefaultLazyEncryptor : Encryptor config not found for property jasypt.encryptor.algorithm, using default value: PBEWithMD5AndDES
2018-04-25 14:03:26.479 INFO 10028 --- [ main] c.u.j.encryptor.DefaultLazyEncryptor : Encryptor config not found for property jasypt.encryptor.keyObtentionIterations, using default value: 1000