删除节点和节点关系

MATCH (a:key)-[r:KEY_WORD]-(b:JAVA) where ID(a) = 47 and ID(b) = 48 DETACH delete a,b,r

查找关联关系

MATCH (info {id: ‘02’})-[:KEY_WORD]->()-[:KEY_WORD]->(fof)

RETURN info.Title, fof.Title

删除节点之间的关系话呢,可以先删除当前节点与其他节点的所有关系

然后在删除当前节点和与此节点有关系的节点

match(a:key)-[r:KEY_WORD]-(b:JAVA)where a.id=’001’ delete r

match(a:key) where a.id=’001’ delete a

match(b:JAVA) where b.id=’01’ delete b