解法一:从上到下计算(后序遍历)

class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
int left = maxDepth(root.left);
int right = maxDepth(root.right);
return Math.max(left,right)+1;
}
}


解法二:从上到下计算(层序遍历)

class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
Deque<TreeNode> queue = new LinkedList<>();
queue.offer(root);
int result = 0;
while (!queue.isEmpty()) {
result++;
int length= queue.size(); //坑点,将queue.size() 直接放入for循环
for (int i = 0; i < length; i++) {
TreeNode poll = queue.poll();
if (poll.left != null) {
queue.offer(poll.left);
}
if (poll.right != null) {
queue.offer(poll.right);
}
}
}
return result;
}
}