Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.

AC的代码:



#include<iostream>
#include<map>
#include<vector>
#include<set>
#include<unordered_map>
#include<climits>
using namespace std;

struct Point
{
int x;
int y;
Point():x(0),y(0) {}
Point(int a,int b):x(a),y(b) {}
};

class Solution {
public:
int maxPoints(vector<Point> &points) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
unordered_map<float,int> mp;
int maxNum = 0;
for(int i = 0; i < points.size(); i++)
{
mp.clear();
mp[INT_MIN] = 0;
int duplicate = 1;
for(int j = 0; j < points.size(); j++)
{
if(j == i) continue;
if(points[i].x == points[j].x && points[i].y == points[j].y)
{
duplicate++;
continue;
}
float k = points[i].x == points[j].x ? INT_MAX : (float)(points[j].y - points[i].y)/(points[j].x - points[i].x);
mp[k]++;
}
unordered_map<float, int>::iterator it = mp.begin();
for(; it != mp.end(); it++)
if(it->second + duplicate > maxNum)
maxNum = it->second + duplicate;
}
return maxNum;
}
};

int main()
{
Solution s;
vector<Point> pp= {Point(0,0),Point(0,0),Point(3,10),Point(0,2),Point(0,2),Point(3,10)};
cout<<s.maxPoints(pp)<<endl;
}


超时的代码:



#include<iostream>
#include<map>
#include<vector>
#include<set>
using namespace std;

struct Point
{
int x;
int y;
Point():x(0),y(0) {}
Point(int a,int b):x(a),y(b) {}
};
struct Line
{
double k;
double t;
Line(double a,double b):k(a),t(b) {}
};
bool operator==(const Point &a,const Point &b)
{
return a.x==b.x&&a.y==b.y;
}
bool operator<(const Point &a,const Point &b)
{
return a.x==b.x?a.y<b.y:a.x<b.x;
}
bool operator==(const Line &a,const Line &b)
{
return a.k==b.k&&a.t==b.t;
}
bool operator<(const Line &a,const Line &b)
{
return a.k==b.k?a.t<b.t:a.k<b.k;
}
class Solution
{
public:
int maxPoints(vector<Point> &points)
{
if(points.empty()||points.size()==1)
return points.size();
map<Line,set<Point> > mp;
int i,j;
int count=0;
for(i=0; i<(int)points.size()-1; i++)
{
for(j=i+1; j<(int)points.size(); j++)
{
Point x=points[i];
Point y=points[j];
double k;
double t;
if(x.x==y.x)
{
k=1e20;
t=x.x;
}
else
{
k=(y.y-x.y)/(y.x-x.x);
t=x.y-x.x*k;
}
mp[{k,t}].insert(x);
mp[{k,t}].insert(y);
}
}
auto start=mp.begin();
while(start!=mp.end())
{
cout<<start->first.k<<" "<<start->first.t<<" "<<start->second.size()<<endl;
set<Point> st=start->second;
multiset<Point> mul(points.begin(),points.end());
auto it=st.begin();
int dup=0;
while(it!=st.end())
{
dup+=mul.count(*it)-1;
it++;
}
if(count<(int)st.size()+dup)
count=st.size()+dup;
start++;
}
return count;
}
};

int main()
{
Solution s;
vector<Point> pp= {Point(0,0),Point(0,0),Point(3,10),Point(0,2),Point(0,2),Point(3,10)};
cout<<s.maxPoints(pp)<<endl;
}