A natural DFS thought. Several pruning tricks can be applied. Please take care of date type(long long).
class Solution { bool _check(string a, string b, string c) { int lenc = c.length(); if (!lenc) return true; if(lenc > 1 && c[0] == '0') return false; int lena = a.length(); int lenb = b.length(); if(lenc < max(lena, lenb) || (lena > 1 && a[0] == '0') || (lenb > 1 && b[0] == '0')) return false; long long va = stoll(a); long long vb = stoll(b); string ssum = to_string(va + vb); int lens = ssum.length(); if (lens > c.length()) return false; string pre = c.substr(0, lens); if(pre != ssum) return false; string rest = c.substr(lens); if (rest.length() > 0 && rest[0] == '0') return false; return _check(b, ssum, rest); } public: bool isAdditiveNumber(string num) { int n = num.length(); for(int i = 1; i <= n / 2; i ++) // lena { string a = num.substr(0, i); for(int j = 1; j <= n - 2 * i; j ++) // lenb { string b = num.substr(i, j); string c = num.substr(i + j); if (_check(a, b, c)) { return true; } } } return false; } };